Given :
As a plane takes off it ascends at a 20 degree angle of elevation.
If the plane has been travelling at an average rate of 290 ft/s and continues to ascend at the same angle.
To Find :
How high is the plane after 10 seconds.
Solution :
Distance travelled by plane, D = 2900 ft.
Angle of elevation, Ф = 20°.
Height gained is given by :
H = 2900 × sin 20°
H = 991.86 ft.
Therefore, height of plane after 10 seconds is 991.86 ft.
Hence, this is the required solution.
Answer:
The perpendicular line would be y = -2x - 4
Step-by-step explanation:
First we must solve the original equation for y.
x - 2y = 7
-2y = -x + 7
y = 1/2x - 7/2
In order to find the equation of this line, we first have to note that perpendicular lines have opposite and reciprocal slopes. Therefore, since the original line has a slope of 1/2, we know the new line will have a slope of -2. Now we can use that information along with the given point in point-slope form to find the equation.
y - y1 = m(x - x1)
y - 2 = -2(x + 3)
y - 2 = -2x - 6
y = -2x - 4
The correct answer is 70 because 420 divided by 6 is 70.
3^(-2) = 1/(3^2) = 1/(3*3) = 1/9
The rule used here is x^(-y) = 1/(x^y) to make the exponent positive.
3^2 turns into 3*3 because the exponent 2 tells us how many copies of the base '3' to multiply out.
