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Alexandra [31]
3 years ago
11

What is the equation of the line that passes through the point (-5, 5) and has a slope of -1

Mathematics
1 answer:
BabaBlast [244]3 years ago
3 0

x-5

Step-by-step explanation:

x-5 is the answer please mention by which method to solve by graphically it is x-5

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What is the area of the rectangle?
avanturin [10]
C
I believe is the right one
6 0
3 years ago
Let f be the function given by f(x)= (x-1)(x^2-4)/x^2-a. For what positive values of a is f continuous for all real numbers x?
9966 [12]

Answer:

a =1 and a=4.

Step-by-step explanation:

The function is

f(x)=\frac{(x-1)(x^2-4)}{x^2-a}

If we want f(x) to be continuous the denominator needs to be different to 0, otherwise f(x) will be indeterminate.

Now, for a a positive real we have that x=\sqrt{a} will annulate the denominator, i.e

(\sqrt{a})^2-a = a-a = 0. But, if a = 1 we have:

f(x)=\frac{(x-1)(x^2-4)}{x^2-1} = \frac{(x-1)(x^2-4)}{(x-1)(x+1)}=\frac{(x^2-4)}{x+1}

so, the value x=\sqrt{a} = \sqrt{1} = 1 won't annulate the denominator.

Now, for a = 4 we have:

f(x)=\frac{(x-1)(x^2-4)}{x^2-4} = x-1

so, the value x=\sqrt{a} = \sqrt{4} = 2 won't annulate the denominator.

In conclusion, for a=1 or a=1, the function will be continuos for all real numbers, since the denominator will never be 0.

4 0
3 years ago
The numbers I circled in red is the questions I have to do can somebody help meh wit dis.Pls and ty .
bija089 [108]
8. 6m + 3n
11. 8r^3 - r^2
12. 3h^2 + 8

hope this helps !
4 0
3 years ago
Solve. PLEASE. The correct answer will receive brainliest
asambeis [7]

Answer:

(-3,0)

Step-by-step explanation:

2x-3+0=-6

7 0
3 years ago
Read 2 more answers
A dilation has center (0,0). Find the image of the point L(6-8) for the scale factor 7.
rjkz [21]

Answer:

D (42,-56)

Step-by-step explanation:

Scale factor means you multiply, so you multiply (6,-8) by 7.

6 x 7 is 42 and 7 x -8 is -56. So your answer is D (42,-56).  

3 0
2 years ago
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