( x^4 - 4 x³ + 2 x² - 4 x + 1 ) : ( x² + 1 ) = x² - 4 x + 1
- x^4 - x²
------------------------
- 4 x³ + x² - 4 x
4 x³ + 4 x
-----------------------
x² + 1
- x² - 1
----------------
R ( x ) = 0
( x^4 - 4 x³ + 2 x² - 4 x + 1) = ( x² + 1 ) ( x² - 4 x + 1 )
Answer:
Step-by-step explanation:
P-6 is an expression, your question is incomplete.
Answer:
-8(7y-8)-3(7y-7)−8(7y−8)−3(7y−7)
Distribute to remove the parentheses.
Collect like terms
-154y+170
Step-by-step explanation:
(x+3 ; y-5)
If you have (-2 ; 3) that means x = -2 and y = 3 so:
(-2+3 ; 3-5) = (1 ; -2)
Answer:
D. y = 12.5x + 15
Step-by-step explanation:
Using the values provided in the table, the only equation that would be valid would be the following...
y = 12.5x + 15
That is because if we substitute any value provided in the table for x , this equation will correctly output the y value shown in the table for the attached x-value. For example, in the table 5 nights (x = 5) should have a total cost of 77.5 (y = 77.5)... Therefore, if we substitute 5 for x in the function it should give us 77.5 which it does.
y = 12.5(5) + 15
y = 62.5 + 15
y = 77.5
