All categories

3 years ago

What is the force on a 1000 kg elevator that is falling freely at 9.8m/s2

Physics

2 answers:

Taya2010 [7]3 years ago

5 0

Explanation:

❀ $\underline {{\underline{ \text{Given} }}}:$

Mass ( m ) = 1000 kg
Acceleration ( a ) = 9.8 m/s²

❀ $\underline{ \underline{ \text{To \: find}}} :$

Force ( F )

❀ $\underline{ \underline{ \text{Solution}}} :$

$\boxed{ \sf{force = mass \times acceleration}}$

Plug the known values :

⟶ $\sf{1000 \times 9.8}$

⟶ $\sf{9800 \: N}$

$\red{\boxed{ \boxed{ \tt{⟿ \: Our \: final \: answer : 9800 \: N}}}}$

Hope I helped !♡

Have a wonderful day / night ! ツ

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Rainbow [258]3 years ago

4 0

Answer:

Since it is falling freely, the only force on it is its weight, w. w = m ⋅ g = 1000kg ⋅ 9.8m s2 = 9800N To draw a Free Body Diagram, draw an elevator cage (I am sure you would get lots of points for drawing it with intricate detail) with a downward force of 9800 N. I hope this helps,

Explanation:

You might be interested in

Your friend is wearing a red coat. When white light hits the coat, some light is reflected, and some is absorbed.

Vilka [71]

Answer:

Orange , yellow, green and blue

red coat absorbs all colors of visible light except red, so red light

is the only light left to bounce off of the coat toward our eyes.

4 0

3 years ago

Help pls i need this right now

pantera1 [17]

Answer:

The x-component of $F_{3}$ is 56.148 newtons.

Explanation:

From 1st and 2nd Newton's Law we know that a system is at rest when net acceleration is zero. Then, the vectorial sum of the three forces must be equal to zero. That is:

$\vec F_{1} + \vec F_{2} + \vec F_{3} = \vec O$ (1)

Where:

$\vec F_{1}$ , $\vec F_{2}$ , $\vec F_{3}$ - External forces exerted on the ring, measured in newtons.

$\vec O$ - Vector zero, measured in newtons.

If we know that $\vec F_{1} = (70.711,70.711)\,[N]$ , $\vec F_{2} = (-126.859, 46.173)\,[N]$ , $F_{3} = (F_{3,x},F_{3,y})$ and $\vec O = (0,0)\,[N]$ , then we construct the following system of linear equations:

$\Sigma F_{x} = 70.711\,N - 126.859\,N +F_{3,x} = 0\,N$ (2)

$\Sigma F_{y} = 70.711\,N + 46.173\,N+F_{3,y} = 0\,N$ (3)

The solution of this system is:

$F_{3,x} = 56.148\,N$ , $F_{3,y} = -116.884\,N$

The x-component of $F_{3}$ is 56.148 newtons.

5 0

3 years ago

A steel beam that is 5.50 m long weighs 332 N. It rests on two supports, 3.00 m apart, with equal amounts of the beam extending

ElenaW [278]

Explanation:

The given data is as follows.

Length of beam, (L) = 5.50 m

Weight of the beam, ( $W_{b}$ ) = 332 N

Weight of the Suki, ( $W_{s}$ ) = 505 N

After crossing the left support of the beam by the suki then at some overhang distance the beam starts o tip. And, this is the maximum distance we need to calculate. Therefore, at the left support we will set up the moment and equate it to zero.

$\sum M_{o} = 0$

$-W_{s} \times x + W_{b} \times 1.5$ = 0

x = $\frac{W_{b} \times 1.5}{W_{s}}$

= $\frac{332 N \times 1.5}{505 N}$

= 0.986 m

Hence, the suki can come (2 - 0.986) m = 1.014 from the end before the beam begins to tip.

Thus, we can conclude that suki can come 1.014 m close to the end before the beam begins to tip.

8 0

4 years ago

1. What are the characteristics of winds?

goldenfox [79]

Answer:

wind has two important things that is direction and speed.

8 0

4 years ago

What is the thinnest soap film (excluding the case of zero thickness) that appears black when illuminated with light with a wave

Llana [10]

Explanation:

It is given that,

The thinnest soap film appears black when illuminated with light with a wavelength of 535 nm, $\lambda=5.35\times 10^{-7}\ m$

Refractive index, $\mu=1.33$

We need to find the thickness of soap film. The soap film appear black means there is an destructive interference. The condition for destructive interference is given by :

$2t=m\dfrac{\lambda}{\mu}$