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Yuki888 [10]
3 years ago
5

Which is capeble of housing astronaughts while they conduct reasearch

Physics
2 answers:
e-lub [12.9K]3 years ago
6 0

Answer:

DING DONG

Explanation:

dusya [7]3 years ago
5 0

Answer:

2

Explanation:

2

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planet a has twice the mass of planet b. from this info what can we conclude about the acceleration due to gravity at the surfac
tangare [24]

Answer: acceleration due to gravity of planet a would be twice that of planet b. Given that the radius are thesame.

Explanation:

Acceleration due to gravity is as a result of the gravitational force of attraction of a planet to its centre.

g = GM/r^2

Where;

g = acceleration due to gravity

G = gravitational constant

M = mass of planet

r = radius of planet

Given that the two planet have the same radius, if the mass of planet a is twice the mass of planet b the the acceleration due to gravity of planet a would be twice that of planet b, because acceleration due to gravity is directly proportional to the mass of the planet.

6 0
3 years ago
Jo wants to find out about floating and sinking. She puts a rubber duck and a bar of soap in a
maks197457 [2]

Answer:

the soap sinks because it is more dense than the duck.

7 0
3 years ago
a bicycle travels at a velocity of -2.33 m/s and has a displacement of -58.3 m. how much time did it take?
Alexandra [31]
We know that velocity is equal to the total displacement of an object over time.
velocity =  \frac{displacement}{time}
Deriving from that equation, we can say that:
t =  \frac{d}{v}
Okay, so here it goes:
t =  \frac{58.3m}{2.33 \frac{m}{s} } \\ t = 25.02s
The bicycle took 25.02 seconds to displace at 58.3 meters.
5 0
3 years ago
Please help me with this please <br><br> I’ll mark you Brainly
ivolga24 [154]
I think it is option (C).

If the answer is helpful then mark me as brainly.
4 0
2 years ago
Find expressions for the force needed to bring an object of mass m from rest to speed v in time t. express your answer in terms
VARVARA [1.3K]
Good morning.

We have that:

\mathsf{V = a\cdot t} , since we have rest in the inicial time.

The acceleration can be found with Newton's Law:

\mathsf{F = m\cdot a\iff a = \dfrac{F}{m}}

Now we put the acceleratin in the velocity equation:

\mathsf{V = \dfrac{F}{m} \cdot t}

We want the force, so, let's isolate F:

\mathsf{V\cdot m = F\cdot t}\\ \\ \\ \boxed{\mathsf{F = \dfrac{V\cdot m}{t}}}

3 0
3 years ago
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