Answer:
Moment of inertia of the system is 289.088 kg.m^2
Explanation:
Given:
Mass of the platform which is a uniform disk = 129 kg
Radius of the disk rotating about vertical axis = 1.61 m
Mass of the person standing on platform = 65.7 kg
Distance from the center of platform = 1.07 m
Mass of the dog on the platform = 27.3 kg
Distance from center of platform = 1.31 m
We have to calculate the moment of inertia.
Formula:
MOI of disk = 
Moment of inertia of the person and the dog will be mr^2.
Where m and r are different for both the bodies.
So,
Moment of inertia
of the system with respect to the axis yy.
⇒ 
⇒ 
⇒ 
⇒
The moment of inertia of the system is 289.088 kg.m^2
Answer:
Explanation:
If the mass of an object is 5 kg, it means that it weighs 5 kg
Hope this helps
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Set up a unit conversion problem, arrange units to convert minutes to seconds, then cancel all time units.
8.3 minutes x (60 seconds/1 minute) x ( 3.00x10^8 meters/1 second) = 149,400,000,000 meters
Since the time is the term with the fewest number of significant figures (2), your answer should only be expressed with two sig figs as well.
1.5x10^11 m
Answer:
88m west and 50m north
Explanation:
1. Find the components of each vector in x and y:
(Please see the picture below)
- Vector 1:
Fx = 52m
Fy = 0m
- Vector 2:
Fx = 44m*cos34.6
Fy = 44m*sin34.6
- Vector 3:
Fx = 0m
Fy = 25m
2. Find the components of the final displacement acting in x and y:
For west direction:
Rx = 52m + 44m*cos34.6 + 0
Rx = 88m
For north direction:
Ry = 0 + 44m*sin34.6 + 25m
Ry = 50m