-A 1000 kg car is rolling down the street at 2.5 m/s. How fast would a 1800 kg car have to collide into it in
1 answer:
1.39m/s
Explanation:
Given parameters:
Mass of car M₁ = 1000kg
Velocity V₁ = 2.5m/s
Mass of second car M₂ = 1800kg
Unknown:
Velocity of second car V₂ = ?
Solution:
For the other body to come to rest, the momentum of the colliding cars must be equal and in the opposite direction:
Momentum of car 1 - momentum of car 2 = 0
Momentum of car 1 = Momentum of car 2
M₁V₁ = M₂V₂
The unknown is V₂
1000x2.5 = 1800V₂
V₂ = = 1.39m/s
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Answer:
12 units
Explanation:
This problem can be solved if we take into account the equation for a sphere
where we took that the radius is 13 units. If we take z=5 and we replace this value in the equation of the sphere we have
where we have taken x2 +y2 because if the equation of a circunference.
In this case the intersection is made when we take z=5, for this value the sphere and the plane coincides in values.
Hence, the radius is 12 units
I hope this is useful for you
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