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Sergeeva-Olga [200]
3 years ago
6

Define the following term. greatest common factor

Mathematics
1 answer:
prohojiy [21]3 years ago
5 0

A GCF ( Greatest Common Factor) is one factor that can be split evenly between the two numbers you have chosen.

For example, the greatest common factor of 4 and 8 would be 4 because this is the greatest number that can be split evenly with the numbers I have chosen.

I hope this helped.

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A certain number was multiplied by 7. 4 was taken away from the product. Finally, that difference was then divided by 9, resulti
marin [14]

Answer:

7

Step-by-step explanation:

To solve this, we have to work backwards. If you divide something by 9, and it equals 5, to figure out the number, we need to multiply by 9. 5*9= 45. If four was taken away, we have to add it to 45, which is 49. If a number *7 is 49, then we have to divide by 7 to get the answer. 49/7=7  

7 0
3 years ago
What is the average (arithmetic mean) of eleven consecutive integers? (1) the average of the first nine integers is 7. (2) the a
laiz [17]

Since eleven is odd, there must be a centra element, which in this case is the sixth. So, we can write 11 consecutive integers as

x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5

Since the arithmetic mean is the sum of the values, divided by how many they are, we have

M = \dfrac{x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5}{11} = \dfrac{11x}{11} = x

So, the mean of 11 consecutive integers is the 6th integer.

4 0
3 years ago
Find the pattern: 1, 1/4, 1/9, 1/16, 1/25
alexandr1967 [171]
The sequence is not geometric or arithmetic because there is no common difference or common ratio between each term.
Not a Geometric or Arithmetic Sequence
8 0
2 years ago
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)
vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

x^{\frac{2}{3}}+y^{\frac{2}{3}}=4

We have to find the equation of tangent line to the given curve at point (-3\sqrt3,1)

By using implicit differentiation, differentiate w.r.t x

\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0

Using formula :\frac{dx^n}{dx}=nx^{n-1}

\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}

\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}

\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}

Substitute the value x=-3\sqrt3,y=1

Then, we get

\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}

\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}

Slope of tangent=m=\frac{1}{\sqrt3}

Equation of tangent line with slope m and passing through the point (x_1,y_1) is given by

y-y_1=m(x-x_1)

Substitute the values then we get

The equation of tangent line is given by

y-1=\frac{1}{\sqrt3}(x+3\sqrt3)

y-1=\frac{x}{\sqrt3}+3

y=\frac{x}{\sqrt3}+3+1

y=\frac{x}{\sqrt3}+4

This is required equation of tangent line to the given curve at given point.

8 0
3 years ago
F=G(m1-m2)/d2 solve formula for m1 plz... thank you
antoniya [11.8K]

1. f = g(m1 - m2)/d2

2. f d2 = g(m1 - m2)

3. f d2/g + m1 - m2

4. f d2/g + m2 = m1

5. [Answer]  m1 = f d2/g + m2


6 0
3 years ago
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