Subtract (3x +5y-4)-(4x+11)
1 answer:
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See the attached figure to better understand the problem
we know that
in the triangle BCD
y²+5.66²=z²-------> y²=z²-5.66²------> equation 1
in the triangle ABC
y²+5.66²=x²-------> y²=x²-5.66²------> equation 2
equals 1 and 2
z²-5.66²=x²-5.66²--------> z²=x²---------> z=x
if z=x then
angle A=45°
angle D=45°
in the triangle ABD
cos 45=z/(5.66*2)-------> z=11.32*cos 45-----> 11.32*√2/2----> 8
z=8
x=8
y²=z²-5.66²------> 8²-5.66²-----> y²=31.96------> y=5.65
the answer is
the value of x is 8
the value of z is 8
the value of y=5.65
we know that
in the triangle BCD
y²+5.66²=z²-------> y²=z²-5.66²------> equation 1
in the triangle ABC
y²+5.66²=x²-------> y²=x²-5.66²------> equation 2
equals 1 and 2
z²-5.66²=x²-5.66²--------> z²=x²---------> z=x
if z=x then
angle A=45°
angle D=45°
in the triangle ABD
cos 45=z/(5.66*2)-------> z=11.32*cos 45-----> 11.32*√2/2----> 8
z=8
x=8
y²=z²-5.66²------> 8²-5.66²-----> y²=31.96------> y=5.65
the answer is
the value of x is 8
the value of z is 8
the value of y=5.65