Find the solutions to x2 = 12
1 answer:
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Y = x² - 4x + 4
y = 2x - 4
Find intersection of L and C:
x² - 4x + 4 = 2x - 4
x² - 6x + 8 = 0
<span> (x - 2)(x - 4) = 0
x = 2 or x = 4
When x = 2 , y = 2(2) - 4 = 0
When x = 4, y = 2(4) - 4 = 4
Points of intersection = A(2, 0) and B(4, 4)
Find the length of AB:
</span>
<span>
Answer: 4.47 units
</span>
y = 2x - 4
Find intersection of L and C:
x² - 4x + 4 = 2x - 4
x² - 6x + 8 = 0
<span> (x - 2)(x - 4) = 0
x = 2 or x = 4
When x = 2 , y = 2(2) - 4 = 0
When x = 4, y = 2(4) - 4 = 4
Points of intersection = A(2, 0) and B(4, 4)
Find the length of AB:
</span>
<span>
Answer: 4.47 units
</span>
Answer:
See below (I hope this helps!)
Step-by-step explanation:
We need to write this in the form y = mx + b.
x + 3y = -12
3y = -x - 12