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photoshop1234 [79]
2 years ago
14

Osborne invested $17,000 in stocks and bonds.

Mathematics
1 answer:
Pani-rosa [81]2 years ago
6 0
SYSTEM OF EQUATIONS

S+B = 17000
0.1S+0.07B=1280

Multiply the first equation by 0.1 and subtract the second equation

0.03B=420
B=14,000
S=3,000
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two dice are rolled until a sum of either 5 or 7 occurs. estimate the probability that a 5 occurs first g
Ierofanga [76]

Answer:

The correct answer is "\frac{2}{5}". A further solution is provided below.

Step-by-step explanation:

According to the question,

The probability of getting a 5 will be:

= \frac{4}{36}

= \frac{1}{9}

The probability of getting a 7 will be:

= \frac{6}{36}

= \frac{1}{6}

The probability of not a 5 nor a 7 will be:

= 1-[\frac{4}{36} +\frac{4}{36} ]

= \frac{26}{36}

= \frac{13}{18}

Now,

For roll of 2 dice,

⇒ P=\frac{1}{9} +{\frac{1}{9}\times (\frac{13}{18} ) }+{(\frac{1}{9} )\times (\frac{13}{18} )^2}+{\frac{1}{9}\times (\frac{13}{18} )^3 }+...

        =\frac{1}{9} [1+\frac{13}{18} +\frac{13^2}{18^2} +\frac{13^3}{18^3} +...]

        =\frac{1}{9} [\frac{1}{1-\frac{13}{18} } ]

        =\frac{1}{9} [{\frac{1}{\frac{5}{8} } ]

        =\frac{2}{5}

6 0
2 years ago
Quiz number 2 question 2 help?
Crazy boy [7]

Answer:

The answer is H.

Step-by-step explanation:

You have to apply mid point formula :

midpoint = ( \frac{x1 + x2}{2} , \frac{y1 + y2}{2} )

let \: (2,8) \: be \: (x1,y1)

let \: (7, - 5) \: be \: (x2,y2)

mipoint = ( \frac{2 + 7}{2} , \frac{8 + ( - 5)}{2} )

midpoint = ( \frac{9}{2} , \frac{4}{2} )

midpoint = (4 \frac{1}{2} ,2)

3 0
3 years ago
Divide use either way to record partial quotient 198÷9
Sauron [17]
It equals 22.............
6 0
3 years ago
(8 x 3) - ( 8 x 1) = x ( 3 - 1
garri49 [273]

Answer:

x=16

Step-by-step explanation:

8 0
3 years ago
You have 23 coins, including nickels, dimes, and quarters. if you have two more dimes than quarters, and the total value of the
Tanzania [10]
You can write three equations in the numbers of nickels (n), dime (d), and quarters (q).
  n + d + q = 23 . . . . . . . there are 23 coins total
  0n +d -q = 2 . . . . . . . . .there are 2 more dimes than quarters
  5n +10d +25q = 250 . .the total value is $2.50

The collection includes 11 nickels, 7 dimes, and 5 quarters.

_____
I used the matrix function of my calculator to solve these equations. You can find q by subtracting from the last equation five times the sum of the first two equations.
  (5n +10d +25q) -5((n +d +q) +(d -q)) = (250) -5(23 +2)
  25q = 125 . . . . . . . simplify
  q = 5
From the second equation,
  d = q +2 = 7
And from the first,
  n = 23 -5 -7 = 11
7 0
3 years ago
Read 2 more answers
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