Answer:
x-ints: (2,0) & (4,0)
y-int: (0,-8)
vertex: (3,1) *highest point of the graph
line of symmetry: x = 3 *x-value in the middle of x-ints
a value is -# *if parabola points done it's negative, if it points up it's positive
Answer:
-4.375
Step-by-step explanation:
Answer:
x = 16
y = 16√3
Step-by-step explanation:
sin(30 degrees) = 1/2
x = 32/2 = 16
cos(30 degrees) = √3/2
y = 16√3
Answer:
118°
Step-by-step explanation:
When two parallel lines are cut by a tranversal, then the exterior angles are supplimentary and the corresponding angles are congruent.
Therefore the angle above (15x - 17)° is also (5x + 17)° and the angle below (5x + 17)° is also (15x - 17)°.
Angles on a straight line adds up to 180°. So to know the measure of the larger angle we must both equations and equal it to 180° to find x in order to know the larger angle.
(5x + 17) + (15x - 17) = 180
5x + 15x + 17 - 17 = 180
20x = 180
20x/20 = 180/20
x = 9°
Nkw let's substitute x = 9 into the equations
5x + 17 =
5(9) + 17 =
= 62°
15x - 17 =
15(9) - 17 =
= 118°
Both equations should add up to be 180°.
Therefore the measure of the largest angle is 118°.
Step-by-step explanation:
y = 3 + 8x^(³/₂), 0 ≤ x ≤ 1
dy/dx = 12√x
Arc length is:
s = ∫ ds
s = ∫₀¹ √(1 + (dy/dx)²) dx
s = ∫₀¹ √(1 + (12√x)²) dx
s = ∫₀¹ √(1 + 144x) dx
If u = 1 + 144x, then du = 144 dx.
s = 1/144 ∫ √u du
s = 1/144 (⅔ u^(³/₂))
s = 1/216 u^(³/₂)
Substitute back:
s = 1/216 (1 + 144x)^(³/₂)
Evaluate between x=0 and x=1.
s = [1/216 (1 + 144)^(³/₂)] − [1/216 (1 + 0)^(³/₂)]
s = 1/216 (145)^(³/₂) − 1/216
s = (145√145 − 1) / 216
