Answer:
is standard equation of hyperbola with vertices at (0, ±9) and foci at (0, ±11).
Step-by-step explanation:
We have given the vertices at (0, ±9) and foci at (0, ±11).
Let (0,±a) = (0,±9) and (0,±c) = (0,±11)
The standard equation of parabola is:
From statement, a = 9
c² = a²+b²
(11)² = (9)²+b²
121-81 = b²
40 = b²
Putting the value of a² and b² in standard equation of parabola, we have
which is the answer.
Answer:
A
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m =
with (x₁, y₁ ) = (4, - 1) and (x₂, y₂ ) = (- 2, 3)
m = =
= -
, thus
y = - x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (- 2, 3) , then
3 = + c ⇒ c = 3 -
=
y = - x +
← in slope- intercept form
Multiply through by 3 to clear the fractions
3y = - 2x + 5 ( add 2x to both sides )
2x + 3y = 5 ( subtract 5 from both sides )
2x + 3y - 5 = 0 ← in general form