What was not a major goal of the constitution?<br> Please help. Tysm!

Mr. Nicholson accepts a job that pays an annual salary of $60,000. In his employment contract, he is given the option of choosin

kodGreya [7K]

Answer:

B

Step-by-step explanation:

Just read and you will see why i say that

3 0

2 years ago

Can someone help me with this math homework please!

Zepler [3.9K]

Answer:

Step-by-step explanation:

1) Least common denominator of 4 and 2 is 4

To eliminate the fraction, each term should be multiplied by 4

ANS:option c

2) Mercury level of water 'y' years = Initial measure +rate of increase 'y' years

0.05 +0.1y = 0.12+0.06y

Ans : Option c

3) 4b +6 = 2 - b + 4

Add 'b' to both sides

4b + b + 6 = 2 + 4

5b + 6 = 6

Subtract 6 from both sides

5b = 6 - 6

5b = 0

b = 0

Ans : Option b

4) Maximum decimal places in this equation is 2. So, to eliminate decimal places, The equation should be multiplied by 100

Ans: option d

5) y +6 = -3y + 26

Add 3y to both the sides

y + 6 + 3y = 26

y + 3y + 6 = 26

4y + 6 = 26

Subtract 6 from both sides

4y = 26-6

4y = 20

Divide bothe sides by 4

y = 20/4

y = 5

Ans: option c

6) '2x' is subtracted from both side of the equation.

Ans: option a - subtraction property of equality

8 0

3 years ago

Keyona had 254 dollars to spend on 9 books. After buying them she had 11 dollars. How much did each book cost ?

guajiro [1.7K]

Answer:

Each book costs $27.

Step-by-step explanation:

Subtract 254 - 11.

254 - 11 = 243

Now, divide 243 by 9.

243 ÷ 9 = 27

Hope this helped!

8 0

3 years ago

Read 2 more answers

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago

What is the missing fraction on the spinner? some1 helppp

Crazy boy [7]

Answer:

7/16

Step-by-step explanation:

3 0

2 years ago

What was not a major goal of the constitution? Please help. Tysm!