Answer:
z(critic) = -2.33
Step-by-step explanation:
In this case this is a population proportion test because the observations are simple random sampled and there is a fixed number of trials with only two possible options. Also, n is big enough.
Since this is a population test, the test statistic is z.
Also, this is a one tailed tast because the claim is that the population proportion is less than 0.57.
In this case, for a 0.01 significance level, z(critic) = -2.33
A = event that you select a black sweater
P(A) = 2/5 since there are 2 black out of 2+3 = 5 total
After you make a selection, we have the event
B = event that you select another black sweater assuming event A has happened already
P(B) = 1/4 because there's 1 black sweater left out of 5-1 = 4 left over
Multiply the probabilities
P(A and B) = P(A)*P(B)
P(A and B) = (2/5)*(1/4)
P(A and B) = 2/20
P(A and B) = 1/10
The answer as a fraction is 1/10
In decimal form, it is 0.1
As a percent, the answer is 10%
Answer:
The answer is C
Step-by-step explanation:
Given that the probability <span>is
modeled by the function
![y=3(257,959)^x[tex] where x is the impurity concentration and y, given as a percent, is the probability of the fuse malfunctioning.\\Then, the probability of the fuse malfunctioning for an impurity concentration of 0.17 is given by [tex]y=3(257,959)^{0.17}=3(8.316941)=24.95](https://tex.z-dn.net/?f=y%3D3%28257%2C959%29%5Ex%5Btex%5D%20%20where%20x%20is%20the%20impurity%20%0Aconcentration%20and%20y%2C%20given%20as%20a%20percent%2C%20is%20the%20probability%20of%20the%20fuse%20%0Amalfunctioning.%5C%5CThen%2C%20the%20%3C%2Fspan%3Eprobability%20of%20the%20fuse%20malfunctioning%20for%20an%20impurity%20concentration%20of%200.17%20is%20given%20by%20%5Btex%5Dy%3D3%28257%2C959%29%5E%7B0.17%7D%3D3%288.316941%29%3D24.95)
Therefore, the <span>probability of the fuse malfunctioning for an impurity concentration of 0.17 is 25% to the nearest percent.</span>
</span>