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deff fn [24]
3 years ago
14

When starting a foot race, a 70.0kg sprinter exerts an average force of 650 N backward on the ground for 0.800 s. How far does h

e travel? a)1.48 m (b) 2.97m (c) 5.95 m (d) 11.9m
Physics
1 answer:
melomori [17]3 years ago
8 0

Answer:

Answer is option b) 2.97m

Explanation:

With the relationship between the force exerted by the runner and the mass that it has, I can determine the acceleration it will have:

F= m × a ⇒ a= (650 kg ×(m/s^2)) / (70kg)= 9.286 (m/s^2)

With the acceleration that prints the force exerted and the time I can determine the distance traveled in the interval:

Distance= (1/2) × a × t^2 = (1/2) × 9.286 (m/s^2) × ((0.8s)^2)= 2.97m

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Explanation:

1)

First of all, we need to find the components of the resultant force along the horizontal and vertical direction.

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Learn more about forces:

brainly.com/question/11411375

brainly.com/question/1971321

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About addition of vectors:

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