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harkovskaia [24]
3 years ago
10

The electric field of an infinite charged plane is constant everywhere in space. true or false.

Physics
1 answer:
Temka [501]3 years ago
7 0
Its True hope this helped 
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An advantage of light microscopes compared to electron microscopes is that light microscopes _____.
ivolga24 [154]
<span>C is the correct answer. Electron microscopes require a vacuum to work, so living cells cannot be seen because they cannot respire. Light microscopes use a ray of visible light instead of a beam of electrons to magnify something so it can be seen by the naked eye. There are two different types of electron microscope: transmission (TEM) and scanning (SEM).</span>
5 0
3 years ago
Read 2 more answers
Select the correct answer.
MariettaO [177]

Answer:

can't explain but is correct

7 0
3 years ago
Julietta and Jackson are playing miniature golf. Julietta's ball rolls into a long. Straight upward incline with a speed of 2.95
Verdich [7]

Answer:

The length of the incline is 3.504 meters.

Explanation:

Let suppose that Julietta's ball decelerates uniformly, then we determine the length of the incline is determined by the following equation of motion:

\Delta s = v_{o}\cdot t +\frac{1}{2}\cdot a \cdot t^{2} (Eq. 1)

Where:

\Delta s - Length of the incline, measured in meters.

v_{o} - Initial speed of the ball, measured in meters per second.

a - Aceleration of the ball, measured in meters per square second.

t - Time, measured in second.

If we know that v_{o} = 2.95\,\frac{m}{s}, t = 1.54\,s and a = -0.876\,\frac{m}{s^{2}}, then the length of the incline is:

\Delta s = \left(2.95\,\frac{m}{s} \right)\cdot (1.54\,s)+\frac{1}{2}\cdot \left(-0.876\,\frac{m}{s^{2}} \right) \cdot (1.54\,s)^{2}

\Delta s = 3.504\,m

The length of the incline is 3.504 meters.

6 0
3 years ago
Suppose that the moment of inertia of a skater with arms out and one leg extended is 3.0 kg⋅m2 and for arms and legs in is 0.90
babymother [125]

Answer:

Her angular speed (in rev/s) when her arms and one leg open outward is 1.56\frac{rev}{s}

Explanation:

Initial moment of inertia when arms and legs in is I_i=0.90 kg.m^{2}

Final moment of inertia when her arms and on leg open outward, I_f=3.0 kg.m^{2}

Initial angular speed w_i=5.2\frac{rev}{s}

Let the final angular speed be w_f

Since external torque on her is zero so we can apply conservation of angular momentum

\therefore L_f=L_i

=>I_fw_f=I_iw_i

=>w_f=\frac{I_iw_i}{I_f}=\frac{0.9\times5.2 }{3.0}\frac{rev}{s}=1.56\frac{rev}{s}

Thus her angular speed (in rev/s) when her arms and one leg open outward is 1.56\frac{rev}{s}

7 0
3 years ago
Sledding down a hill, you are traveling at 10 m/s when you reach the bottom. You (inertia 80 kg ) then move across horizontal sn
RSB [31]

Answer:

V = 0.32 m /s

Explanation:

Momentum of the man on the sledge along with sledge

= (80+8) x 10 = 880 kg. m/s When the man jumps off the sledge , the velocity of the sledge will remain intact at 10 m/s

When the sledge hits the boulder and bounces back the momentum of the sledge - boulder system will remain conserved .

change in momentum of sledge = 8 x (10 +6 )

= 128  kg m/s

Change in the momentum of boulder

= 400 V -0

= 400V

400V = 128

V = 0.32 m /s

5 0
3 years ago
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