Answer:
7.89 m/s
Explanation:
Given that
Width of the river, b1 = 12 m
Width of the river, b2 = 5.8 m
Depth of the river, d1 = 2.7 m
Depth of the river, d2 = 0.85 m
Speed of the river, v1 = 1.2 m/s
Speed of the river, v2 = ?
Area of the river before the rapid, a1 = 12 * 2.7 = 32.4 m²
Area of the river after the rapid, a2 = 5.8 * 0.85 = 4.93 m²
To solve this question, we use a relation between the speed of the river and the volume of the river. We say,
Area1 * velocity1 = Area2 * velocity2, and when we substitute the values for each other we have
32.4 * 1.2 = 4.93 * v2
38.88 = 4.93v2
v2 = 38.88 / 4.93
v2 = 7.89 m/s
Therefore, the speed of the river after the rapid is 7.89 m/s
Answer:
The 10 rules of badminton are as follows:
1. A game starts with a coin toss. Whoever wins the toss gets to decide whether they would serve or receive first OR what side of the court they want to be on. The side losing the toss shall then exercise the remaining choice.
2. At no time during the game should the player touch the net, with his racquet or his body.
3. The shuttlecock should not be carried on or come to rest on the racquet.
4. A player should not reach over the net to hit the shuttlecock.
5. A serve must carry cross court (diagonally) to be valid.
6. During the serve, a player should not touch any of the lines of the court, until the server strikes the shuttlecock. During the serve the shuttlecock should always be hit from below the waist.
7. A point is added to a player's score as and when he wins a rally.
8. A player wins a rally when he strikes the shuttlecock and it touches the floor of the opponent's side of the court or when the opponent commits a fault. The most common type of fault is when a player fails to hit the shuttlecock over the net or it lands outside the boundary of the court.
9. Each side can strike the shuttlecock only once before it passes over the net. Once hit, a player can't strike the shuttlecock in a new movement or shot.
10. The shuttlecock hitting the ceiling, is counted as a fault.
Explanation:
It’s coming in contact with more air molecules than I would if it was in a ball because there is less surface area
the object distance of both lenses are positive.
