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Liula [17]
3 years ago
13

La probabilidad de que el estudiante A apruebe un examen de MM-100 es 0.6, la probabilidad de que apruebe un estudiante B es 0.4

y la probabilidad de que ambos estudiantes aprueben es 0.3. ¿Cual es la probabilidad de que apruebe el estudiante B dado que el estudiante A aprueba.?
Mathematics
1 answer:
ivanzaharov [21]3 years ago
6 0

Answer:

0.5 = 50% probabilidad de que apruebe el estudiante B dado que el estudiante A aprueba.

Step-by-step explanation:

La probabilidad condicional :

P(B|A) = \frac{P(A \cap B)}{P(A)}

En el cual:

P(B|A) es la probabilidad de que ocurra el evento B, dado que A sucedió.  

P(A \cap B) es la probabilidad de que ocurran tanto A como B.  

P(A) es la probabilidad de que ocurra A.

En esta pregunta :

Evento A: Estudiante A aprueba.

Evento B: Estudiante B aprueba.

La probabilidad de que el estudiante A apruebe un examen de MM-100 es 0.6

Entonces P(A) = 0.6

La probabilidad de que ambos estudiantes aprueben es 0.3

Entonces P(A \cap B) = 0.3

¿Cual es la probabilidad de que apruebe el estudiante B dado que el estudiante A aprueba.?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3}{0.6} = 0.5

0.5 = 50% probabilidad de que apruebe el estudiante B dado que el estudiante A aprueba.

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A poll asks shoppers at the mall how many cups of water they typically drink in a day. The results of the poll are listed below.
juin [17]

Answer:

D 9.5

Step-by-step explanation:

Write data in increasing order.

3, 5, 5, 6, 6, 6, 7, 7, 8, 8, 8, 8, 8, 8, 9, 9, 10, 10, 10, 10, 11

Find the median

<u>3, 5, 5, 6, 6, 6, 7, 7, 8, 8,</u> 8, <u>8, 8, 8, 9, 9, 10, 10, 10, 10, 11</u>

Median is 8

Lower half of the data is : 3, 5, 5, 6, 6, 6, 7, 7, 8, 8,

First quartile is the median of the lower half of the data=6+6 /2 =6

Upper half of the data is: 8, 8, 8, 9, 9, 10, 10, 10, 10, 11

The Third quartile is the median of the upper half=9+10 / 2 = 9.5

<u />

3 0
3 years ago
Read 2 more answers
Anyone know the awnser to this?
iragen [17]

Answer:

61

Step-by-step explanation:

straight line = 180 degree

to find the measure of angle QPR,

subtract 119 from 180

=>            180-119

=>            61

angle QPR = 61 degree

6 0
2 years ago
Read 2 more answers
What is an equation of the line that is parallel to y=9−5x and passes through (0, 8) ?
TEA [102]

Answer:

y = -5x Y8  

Step-by-step explanation:

Parallel lines have the same slope.

Your function is

y = 9 − 5x = -5x+ 9

slope = -5

The parallel line

The line must have slope = -5 and include (0, 8), so

8 = -5×(0) + b

8 = 0 + b

b = 8

The equation for the parallel line is

y = -5x + 8

In the diagram below, the red line is the graph of y = 9 -5x.

The parallel blue line is the graph of y = -5x + 8.

8 0
3 years ago
What is the slope-intercept form of this equation?
quester [9]
8X+6Y=12

Here's how you solve it:

Just isolate y by itself to get y-intercept form.
This is the formula: Y=MX+B

M is the slope or the number next to X in the original problem.

First:
6Y=-8X+12

Next:
divided everything by 6

Y=-4/3+2

I think the answer is A!


3 0
3 years ago
Read 2 more answers
Can someone please teach me how to do this? You can please do like 2 questions and please explain exactly how you got the answer
spayn [35]

All of these questions require one thing: trigonometric functions.

There are 3 main trigonometric functions, which can only be used on right triangles: sine, cosine, and tangent.

Sine = opposite / hypotenuse

Cosine = adjacent / hypotenuse

Tangent = opposite / adjacent

When trying to figure out what function to use, we always start by looking from the angle. Take problem a, for example. Looking from angle E, of which the value is not given, we have the side opposite and the side adjacent. Therefore, we should use the tangent function.

---The hypotenuse is always the longest side of the triangle. It is never considered the opposite or adjacent side.

Let's set up our function with the given information from problem a.

tan(x) = 9.7 / 5.2

---The tangent of an unknown angle is equal to the quotient of the opposite side and the adjacent side.

Now, solving for the value of x will require a calculator. We'll need to use what's called an inverse trigonometric function. Most calculators have these directly above the regular trigonometric functions, and the inverse functions are accessed using a "second" key.

---Ensure that your calculator is in degrees, not radians!

x = tan^-1(9.7 / 5.2)

x = 61.805 = 62 degrees

Next, let's take a look at problem b. This time, we're solving for a side length instead of an angle. But, we're still going to start by looking from our angle.


Looking from the 38 degree angle, we are given the adjacent side and an unknown hypotenuse. Therefore, we should use the cosine function.

cosine(38) = 53.1 / r

---The cosine of a 38 degree angle is equal to the quotient of 53.1 and an unknown hypotenuse, r.

Use your algebra skills to isolate the variable r.

r * cosine(38) = 53.1

r = 53.1 / cosine(38)

---From here, all you need to do is plug this into your calculator. Since we are solving for a side length (and given an angle), we are just using the regular trigonometric function buttons on the calculator.

r = 67.385 = 67.4 units

Hope this helps!

4 0
2 years ago
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