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3 years ago

Draw a model and write an equation to represent 4 times as many as 3 is 12 explain your work

Mathematics

2 answers:

trasher [3.6K]3 years ago

7 0

4x3=12. Think of it like this... 4 times as many as 3 is 12 (x)
(=)

So 4 times is 4 multiplied by....... 3 is just 3.... is means equals.... and the answer is 12. Your welcome, I hope I helped.

Ymorist [56]3 years ago

7 0

Answer:

The required equation is $4\times 3=12$ and the required model is shown in figure 1.

Step-by-step explanation:

Consider the provided information.

We need to draw a model and write an equation to represent 4 times as many as 3 is 12.

4 times as many as 3 can be written as:

$4\times 3$

This expression is equal to 12. Thus the combined equation is:

$4\times 3=12$

The required model is shown in figure 1:

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X+16=24hvvcgcfcycdfdxfxxdgfv

zaharov [31]

To do solve this you must isolate x. First subtract 16 to both sides (what you do on one side you must do to the other). Since 16 is being added to x, subtraction (the opposite of addition) will cancel it out (make it zero) from the left side and bring it over to the right side.

x + (16 - 16) = 24 - 16

x = 8

Check:

8 + 16 = 24

24 = 24

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0

3 years ago

Read 2 more answers

Sasha can mow of an acre of grass in 45 minutes. How many acres of grass does Sasha mow per hour?

AleksAgata [21]

Answer:

45 minutes =34 hour. → Sasha mows 48=12 of an acre in 44=1 hour.

Step-by-step explanation:

5 0

2 years ago

What is the equation of a circle with a center (-2, 3) and a radius r = 5?

qwelly [4]

The formula for the equation of a circle is:
(x - h)^2 + (y - k)^2 = r^2

(h, k) is the center.

So the equation would be:
(x + 2)^2 + (y - 3)^2 = 5^2
or
(x + 2)^2 + (y - 3)^2 = 25

6 0

2 years ago

A circle has centre (3,0) and radius 5. The line y = 2x + k intersects the circle in two points. Find the set

lara [203]

A circle with center $(3,0)$ and radius $5$ has equation

$(x-3)^2+y^2=25 \iff x^2 + y^2- 6 x = 16$

If we substitute $y=2x+k$ in this equation, we have

$x^2+(2x+k)^2-6x=16 \iff 5x^2+(4k-6)x+k^2-16=0$

This equation has two solutions (i.e. the line intersects the circle in two points) if and only if the determinant is greater than zero:

$\Delta=b^2-4ac=(4k-6)^2-4\cdot 5\cdot (k^2-16)>0$

The expression simplifies to

$-4 (k^2 + 12 k - 89)>0 \iff k^2 + 12 k - 89$

The solutions to the associated equation are

$k^2 + 12 k - 89=0 \iff k=-6\pm 5\sqrt{5}$

So, the parabola is negative between the two solutions:

$-6-5\sqrt{5}$

8 0

3 years ago

I’m trying to figure out what the answer is to these questions?

hram777 [196]

To find corresponding angles and sides, you look at the name of the figure and see which one correlates.

QUESTION 6
ABC and DEF
Corresponding Angles-
A,D
B,E
C,F
Corresponding Sides-
AB, DE
BC, EF
AC, DF

QUESTION 7
FGHI and KLMN
Corresponding angles-
F,K
G,L
H,M
I,N
Corresponding Sides-
FG,KL
GH,LM
HI,MN
FI,KN

8-
x=12

9-
y= 25.6

10-
z= 23 1/3

11-
36=k

6 0

3 years ago