Find the extrema of the function y=cos2x
1 answer:
Answer:
Step-by-step explanation:
Find derivative of the function:
y' = -2·sin(2·x)
-2·sin(2·x) = 0
x1 = 0
x2 = 3.142
f(0) = 1
f(3.142) = 1
Answer
fmin = 1, fmax = 1
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