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3 years ago

8

Find the extrema of the function y=cos2x

1 answer:

marishachu [46]3 years ago

4 0

Answer:

Step-by-step explanation:

Find derivative of the function:

y' = -2·sin(2·x)

-2·sin(2·x) = 0

x1 = 0

x2 = 3.142

f(0) = 1

f(3.142) = 1

Answer

fmin = 1, fmax = 1

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