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3 years ago

AYUDAAA, ES UN EXAMEN PARA HOY!!Lo empiezo a seguir si me dan la respuestas correctas! :)

Mathematics

1 answer:

Alika [10]3 years ago

7 0

Answer:

1/2 , .5 , 50%

Step-by-step explanation:

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What Does Y intercept =

anastassius [24]

The y-intercept of a line is where the line goes across the y line.

Does that answer your question?

4 0

3 years ago

Msty and yesenia have a group of base ten blocks. misty had six more block than yesenia. yesenias blocks represent 17. together

Inessa05 [86]

yesenia has 9 blocks. misty has 15.

15 + 9 = 22.

for the values of the blocks, yesenia has 17 and misty has 68.

17 + 68 = 85.

hope i helped!

4 0

3 years ago

The graph of f passes through (-6,9) and is perpendicular to the line that has an x-intercept of 8 and a y-intercept of -24 the

Valentin [98]

Given:

The graph of f passes through (-6,9).

It is perpendicular to the line that has an x-intercept of 8 and a y-intercept of -24.

To find:

The equation of the function f.

Solution:

The equation of line on which graph of f is perpendicular, is

$\dfrac{x}{a}+\dfrac{y}{b}=1$

where, a and b are x and y intercepts respectively.

$\dfrac{x}{8}+\dfrac{y}{-24}=1$

Multiply both sides by 24.

$3x-y=24$

Slope intercept form is

$y=3x-24$

Slope of this line is 3 and y-intercept is -24.

Product of slopes of two perpendicular lines is -1.

Let the slope of f is m. So,

$m\times 3=-1$

$m=-\dfrac{1}{3}$

Slope of m is -1/3 and it passes through (-6,9). So, the equation of function f is

$y-y_1=m(x-x_1)$

$y-9=-\dfrac{1}{3}(x-(-6))$

$y-9=-\dfrac{1}{3}(x+6)$

$y-9=-\dfrac{1}{3}x-2$

$y=-\dfrac{1}{3}x-2+9$

$y=-\dfrac{1}{3}x+7$

Put y=f(x).

$f(x)=-\dfrac{1}{3}x+7$

Therefore, the required function is $f(x)=-\dfrac{1}{3}x+7$ .

7 0

3 years ago

A. 28.1 cm squared <br> B. 3.8 cm squared <br> C. 11.3 cm squared <br> D. 56.2 cm squared

Colt1911 [192]

Answer:

A. 28.1 cm^2

Step-by-step explanation:

a = bh

a = (7.6)(3.7)

a = 28.12 cm^2

a = 28.1 cm^2

6 0

3 years ago

How to do this question? : (

Lostsunrise [7]

How to do what question

5 0

3 years ago

AYUDAAA, ES UN EXAMEN PARA HOY!!Lo empiezo a seguir si me dan la respuestas correctas! :)​

AYUDAAA, ES UN EXAMEN PARA HOY!!Lo empiezo a seguir si me dan la respuestas correctas! :)