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2 years ago

Help if you a real one! C”mon pls click on me!!

Mathematics

1 answer:

dem82 [27]2 years ago

6 0

Answer:

D. $\frac{AB}{VW}$ = $\frac{CD}{XY}$

Step-by-step explanation:

You have to make sure that the proportions of both figures are matched correctly. These are the pairings:

AB is like VW but bigger.

CB is like XW but bigger.

AE is like VZ but bigger.

CD is like XY but bigger.

ED is like ZY but bigger.

Thus, the only correct comparison would have been $\frac{AB}{VW}$ = $\frac{CD}{XY}$

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A net of a building block is shown below. What is the total surface area of the building block? *

777dan777 [17]

Answer:

where

Step-by-step explanation:

6 0

1 year ago

PLEASE PLEASE PLEASE<br> HELP ME!!!!!

Bond [772]

Answer:

3 adjacent

4. complementary

4 0

2 years ago

Help please this my second time posting this please help

Nesterboy [21]

Answer:

x = √30

Step-by-step explanation:

From small triangle BDC:

using Pythagorean theorem

CB² = BD² + DC²

x² = BD² + 3²

Fron triangles BDC and ADB.

ΔBDC has long leg BD and short leg DC.

ΔADB has long leg AD and shirt leg BD.

AD : BD = BD : DC

7 : BD = BD : 3

7*3 = BD*BD

BD² = 7*3 = 21

x² = BD² + 3² = 21+9 = 30

x² = 30

x = √30

4 0

2 years ago

1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.

german

Answer:

Step-by-step explanation:

To write the form of the partial fraction decomposition of the rational expression:

We have:

$\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}$

Using partial fraction decomposition to find the definite integral of:

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx$

By using the long division method; we have:

$x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }$

$- 2x^3 -16x^2-40x$

$x+ 20$

So;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}$

By using partial fraction decomposition:

$\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}$

$= \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}$

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now; we have to relate like terms on both sides; we have:

A + B = 1 ; 2A - 10 B = 20

By solvong the expressions above; we have:

$A = \dfrac{5}{2}$ $B = \dfrac{3}{2}$

Now;

$\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}$

Thus;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}$

Now; the integral is:

$\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx$

$\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}$

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.

4 0

2 years ago

a solution of trioxonitrate (v) acid contained 0.67g in 100cm³. 31cm³ of this solution neutralized 25cm³ of a sodium trioxocarbo

FinnZ [79.3K]

Answer:

0.67 / 100 : 31^3 : 31^3 / 25cm^3

x 10

0.67 / 100 = 67 / 10000000 grams/cm : 29791 / 15625 / 29791

149253.731 : 0.52

divide by 1000

= 149.253731

= 149.3 kg

Ratio kg = 149.3 : 0.5

Step-by-step explanation:

Mole Ratio

The mole ratio compares the number of moles in a balanced equation.

This is the comparison between the coefficients in front of the chemical formulas.

If a formula lacks a coefficient, it is the same as saying there is 1 mole of that species.

Mole ratios are used to predict how much product a reaction forms or to determine how much reactant is needed to make a set amount of product.

Mole Ratio Units

Mole ratio units are either mole:mole or else it is a dimensionless number because the units cancel out. For example, it's fine to say a ratio of 3 moles of O2 to 1 mole of H2 is 3:1 or 3 mol O2: 1 mol H2.

5 0

2 years ago