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Svetllana [295]
3 years ago
15

Help if you a real one! C”mon pls click on me!!

Mathematics
1 answer:
dem82 [27]3 years ago
6 0

Answer:

D. \frac{AB}{VW} = \frac{CD}{XY}

Step-by-step explanation:

You have to make sure that the proportions of both figures are matched correctly. These are the pairings:

AB is like VW but bigger.

CB is like XW but bigger.

AE is like VZ but bigger.

CD is like XY but bigger.

ED is like ZY but bigger.

Thus, the only correct comparison would have been  \frac{AB}{VW} = \frac{CD}{XY}

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A piece of wood is divided into two pieces in the ratio of 2:5. One piece is 10 cm long so how long is the other piece?
klio [65]

Answer:

The length of the pother piece of the wood is 25 cm.

Step-by-step explanation:

Let the length of a piece of wood is x such that the ratio of two pieces is 2:5. Two pieces are 2x and 5 x

Length of the first piece is 10 cm. It means, 2x = 10 i.e. x = 5

We have considered that the length of other piece is 5x. It means 5×5 = 25 cm.

Hence, the length of the pother piece of the wood is 25 cm

8 0
3 years ago
5) Two machines M1, M2 are used to manufacture resistors with a design
Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that \mu = 1050, \sigma = 100

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1050}{100}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1050}{100}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.6915 - 0.0668 = 0.6247.

M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that \mu = 1000, \sigma = 120

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1000}{120}

Z = 0.83

Z = 0.83 has a pvalue of 0.7967.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1000}{120}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033

0.7967 - 0.2033 = 0.5934

M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

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If the x-values increase as the y-values decrease on a line graph, the slope of the line is
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