Answer:
TRUE
Step-by-step explanation:
A quadratic equation can be found that will go through any three distinct points that ...
- satisfy the requirements for a function
- are not on the same line
_____
The key word here is "may." You will not be able to find a quadratic intersecting the three points if they do not meet both requirements above.
2x-3 > 11 - 5x
2x + 5x > 11 + 3
7x > 14
x > 14/7
x > 2
14 is always 15 is sometimes 16 is sometimes
X=-4 you have to substitue first so you put the equation where the X is and then you would distribute and then add the numbers that have the common exponent
