Lou and Jacob each sold 200 pieces of jewelry. If 20% of Lou’s sales were rings, and Jacob sold 35 rings, who sold more rings? H

Question

balandron [24]

3 years ago

14

Lou and Jacob each sold 200 pieces of jewelry. If 20% of Lou’s sales were rings, and Jacob sold 35 rings, who sold more rings? H

ow many more? Use the drop-down menus to explain your answer

Mathematics

2 answers:

n200080 [17] · Answer 1 · 2022-02-19T09:09:15+03:00

n200080 [17]3 years ago

6 0

Lou sold more rings because if you multiply 200 by .20 it will be 40 which means he sold 40 rings. he sold 5 more rings than Jacob.

Orlov [11] · Answer 2 · 2022-02-19T10:22:11+03:00

Answer: Lou sold more rings ( 40). He sold 5 more rings than Jacob

Step-by-step explanation:

Hi, to solve this problem we have to analyze the information given:

<em>Lou: 200 pieces sold- 20% were rings </em>

<em>Jacob: 200 pieces sold - 35 were rings </em>

We have to multiply the pieces sold by Lou (200) by the percentage given in the decimal form (20% /100=0.2), to obtain the numbers of rings sold by Lou.

Mathematically speaking:

200 x 0.2 = 40 rings

40 (Lou)> 35 (Jacob)

Lou sold more rings (40 > 35). He sold 5 more rings than Jacob (40-35 =5)