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3 years ago

Can you solve this equation please √{√[S + 5972 – 1111²]}

Mathematics

2 answers:

nasty-shy [4]3 years ago

8 0

The answer you want is 20!

Tasya [4]3 years ago

4 0

Your answer is 20
➌ Calculate the following: √{√[S + 5972 – 1111²]}

Answer = 20

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∠A and ∠B are vertical angles. If ∠A=8x+14 and ∠B=2x+50, what is m∠B?

Maslowich

Answer:

∠B = 62°

Step-by-step explanation:

Because ∠A and ∠B are vertical angles they are equal hence we can write

∠A = ∠B

8x + 14 = 2x + 50

Now we have to solve for x

To do so, subtract 2x on both sides of the equation:

6x + 14 = 50

Now, subtract 14 on both sides of the equation

6x = 36

Now, divide 6 on both sides of the equation

x = 6

To find m∠B you have to you have to plug in x = 6 back into the ∠B equation

∠B = 2(6) + 50

∠B = 62°

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1 year ago

Evaluate the function f(x) at the given numbers (correct to six decimal places). F(x) = x2 − 5x x2 − x − 20 , x = 5.5, 5.1, 5.05

exis [7]

we are given

$f(x)=\frac{x^2-5x}{x^2-x-20}$

Firstly, we will simplify it

$f(x)=\frac{x(x-5)}{(x-5)(x+4)}$

$f(x)=\frac{x}{(x+4)}$

At x=5.5:

we can plug x=5.5

$f(5.5)=\frac{5.5}{(5.5+4)}$

$f(5.5)=0.578947$

At x=5.1:

we can plug x=5.1

$f(5.1)=\frac{5.1}{(5.1+4)}$

$f(5.1)=0.56043956$

At x=5.05:

we can plug x=5.05

$f(5.05)=\frac{5.05}{(5.05+4)}$

$f(5.05)=0.558011$

At x=5.01:

we can plug x=5.01

$f(5.01)=\frac{5.01}{(5.01+4)}$

$f(5.01)=0.5560488$

At x=5.005:

we can plug x=5.005

$f(5.005)=\frac{5.005}{(5.005+4)}$

$f(5.005)=0.5558023$

At x=5.001:

we can plug x=5.001

$f(5.001)=\frac{5.001}{(5.001+4)}$

$f(5.001)=0.5556049$

At x=4.9:

we can plug x=4.9

$f(4.9)=\frac{4.9}{(4.9+4)}$

$f(4.9)=0.5505617$

At x=4.95:

we can plug x=4.95

$f(4.95)=\frac{4.95}{(4.95+4)}$

$f(4.95)=0.5530726$

At x=4.99:

we can plug x=4.99

$f(4.99)=\frac{4.99}{(4.99+4)}$

$f(4.99)=0.55506117$

At x=4.995:

we can plug x=4.995

$f(4.995)=\frac{4.995}{(4.995+4)}$

$f(4.995)=0.55503085$

At x=4.999:

we can plug x=4.999

$f(4.999)=\frac{4.999}{(4.999+4)}$

$f(4.999)=0.55550616$

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4 years ago