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motikmotik
2 years ago
7

A plane is going to fly 300 miles at a planned speed of 530 mph. The flight will have an average headwind of w miles per hour th

e entire time, meaning the plane is flying directly against the wind. The time
Tin hours of the flight is a function of the speed of the headwind w, in mph, and can be modeled by

300

T(W) =

530-W


I need help with the bottom part. What does t(110) mean I’m this situation etc.
Mathematics
1 answer:
vladimir2022 [97]2 years ago
7 0

Answer:

T(100) represents that the plane flies against the wind at 110mph for 0.714 hours

Step-by-step explanation:

Given

w = headwind

T = time

Model:

<em />T(w) = \frac{300}{530 - W}<em> -- This was not properly presented in your question</em>

Required

What does T(110) means

First, we calculate T(110):

Substitute 110 for w in T(w) = \frac{300}{530 - W}

The expression becomes

T(110) = \frac{300}{530 - 110}

T(110) = \frac{300}{420}

T(110) = 0.714<em> -- approximated</em>

<em>T(100) represents that the plane flies against the wind at 110mph for 0.714 hours</em>

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Answer:

Niles and Bob were traveling for 6 hours.

Step-by-step explanation:

The speed or rate at which an object is moving can be computed using the formula:

s=\frac{d}{t}

Here:

<em>s</em> = speed

<em>d</em> = distance traveled

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It is provided that Niles and Bob sailed at the same time for the same length of time.

Speed of Niles sailboat is, <em>s</em>₁ = 6 mph.

Distance traveled by Niles' sailboat is, <em>d</em>₁ = 36 miles.

Speed of Bob's sailboat is, <em>s</em>₂ = 16 mph.

Distance traveled by Bob's sailboat is, <em>d</em>₂ = 96 miles.

It took both Niles and Bob the same time to travel the respective distance.

Compute the time it took Niles to travel 36 miles at 6 mph speed as follows:

t_{1}=\frac{d_{1}}{s_{1}}

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It took Niles 6 hours to travel 36 miles at 6 mph speed.

Compute the time it took Bob to travel 96 miles at 16 mph speed as follows:

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It took Bob 6 hours to travel 96 miles at 16 mph speed.

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x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v
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Then the surface integral is equivalent to

\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du

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Answer:

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Step-by-step explanation:

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