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Mrrafil [7]
3 years ago
8

Point B is halfway between A and C. The distance from C to D is the same as the distance from D to E, which is the same as the d

istance from E to F. The area of triangle ACF is 180 cm2. How many square centimeters is the shaded area of triangle BCE?

Mathematics
1 answer:
jek_recluse [69]3 years ago
8 0

Answer:

60

Step-by-step explanation:

area of triangle ACF is (1/2) (AC) (CF) = 180

area of triangle BCE = (1/2) (BC) (CE)

BC = AC/2

CE=(2/3) CF

so (1/2) (BC) (CE) = (1/2) (AC/2) (2/3)CF = (1/2)(2/3)(180) = 60 sq cm

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Answer:

A darts player practices throwing a dart at the bull’s eye on a dart board. Her probability of hitting the bull’s eye for each throw is 0.2.

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The number F of unsuccessful throws till the first bull’s eye follows a geometric

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If the first bull’s eye is on the third throw, there must be two failures:

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2

q = (0.8)2

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(b) Find the probability that she will have at least three failures before her first

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We want the probability of F ≥ 3. This can be found in two ways:

P(F ≥ 3) = P(F = 3) + P(F = 4) + P(F = 5) + P(F = 6) + . . .

= p

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q + p

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q + p

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q + p

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q + . . . (geometric series with ratio p)

=

p

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=

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1 − 0.8

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Alternatively,

P(F ≥ 3) = 1 − (P(F = 0) + P(F = 1) + P(F = 2))

= 1 − (q + pq + p

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)

= 1 − 0.488 = 0.512.

(c) How many throws on average will fail before she hits bull’s eye?

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is

E[F] = p

q

=

0.8

0.2

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This is a polynomial of the form:

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\begin{gathered} p=0 \\ (x-a)^b(x-c)^d\ldots(x-e)^f=0 \end{gathered}

The values of x are then found by setting each factor to zero:

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The multiplicity are the exponents of the factor where we got the x-intercept, therefore, the multiplicities are:

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To determine the end behavior of the polynomial we need to know the sign of the leading coefficient that is, the sign of the coefficient of the term with the highest power. In this case, the leading coefficient is -2, since the degree of the polynomial is an even number this means that both ends are down. If the leading coefficient were a positive number then both ends would go up. In the case that the leading coefficient was positive and the degree and odd number then the left end would be down and the right end would be up, and if the leading coefficient were a negative number and the degree an odd number then the left end would be up and the right end would be down.

Part C. A sketch of the graph is the following:

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