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The general equation of a circle is x^2 + y^2 = r^2. Here we know that the circle passes thru two points: (-3,2) and (1,5). Given that a third point on the circle is (-7, ? ), find the y-coordinate of this third point.
Subst. the known values (of the first point) into this equation: (-3)^2 + (2)^2 = r^2. Then 9 + 4 = 13 = r^2.
Let's check this. Assuming that the equation of this specific circle is
x^2 + y^2 = r^2 = 13, the point (1,5) must satisfy it.
(1)^2 + (5)^2 = 13 is not true, unfortunately.
(1)^2 + (5)^2 = 1 + 25 = 26 (very different from 13).
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Answer:
x=7
Step-by-step explanation:
Answer: the lengths of the line segments. hope this helps!
Step-by-step explanation:
Answer:
y = 3
Step-by-step explanation:
substitute the x in 2x - y = 7 by x = 3y - 4 and then solve
2(3y - 4) - y = 7
<em>Distribute the 2 into the parenthesis</em>
6y - 8 -y = 7
<em>combine like terms</em>
5y - 8 = 7
<em>add 8 on both sides</em>
5y = 15
<em>divide by 5 on both sides to isolate the y-value</em>
y = 3
Answer:
Step-by-step explanation:
-3y+11=20
-3y=20-11
y=9/-3
y=-3
