Area of the square:
A = s²
and s = AB = sqrt ( ( 4 - 1 )² + ( 3 - 1 )² )
s = √ ( 9 + 4 ) = √ 13
A = ( √13 )² = 13
Answer: Area of the square is 13 units².
Answer:
Step-by-step explanation:
Split up this Isosceles, Right Triangle into two congruent smaller right triangles. The reflexive side [the line that splits them apart] is 6 units, and both legs are 8 units, leaving the hypotenuses to AUTOMATICALLY be 10 units, according to the Pythagorean Theorem:
With this Pythagorean Triple, we know that our dimensions are correct. Now, to find the perimeter, just add up all the sides EXCEPT for the divider:
![\displaystyle 2[10] + 2[8] = 20 + 16 = 36](https://tex.z-dn.net/?f=%5Cdisplaystyle%202%5B10%5D%20%2B%202%5B8%5D%20%3D%2020%20%2B%2016%20%3D%2036)
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To solve this problem you must apply the proccedure shown below:
1. Let's round the value to the nearest hundredth. As you can see, the digit 8 is in the thousandths place and is greater than 5, therefore, you must round up to 0.038.
2. Now express the value as a single digit times a power of 10, as following:
x
Therefore, the answer is: x
Answer:48
Step-by-step explanation:
9 times 6 is 54, then you subtract the 6 and get 48
Answer:
yp = -x/8
Step-by-step explanation:
Given the differential equation: y′′−8y′=7x+1,
The solution of the DE will be the sum of the complementary solution (yc) and the particular integral (yp)
First we will calculate the complimentary solution by solving the homogenous part of the DE first i.e by equating the DE to zero and solving to have;
y′′−8y′=0
The auxiliary equation will give us;
m²-8m = 0
m(m-8) = 0
m = 0 and m-8 = 0
m1 = 0 and m2 = 8
Since the value of the roots are real and different, the complementary solution (yc) will give us
yc = Ae^m1x + Be^m2x
yc = Ae^0+Be^8x
yc = A+Be^8x
To get yp we will differentiate yc twice and substitute the answers into the original DE
yp = Ax+B (using the method of undetermined coefficients
y'p = A
y"p = 0
Substituting the differentials into the general DE to get the constants we have;
0-8A = 7x+1
Comparing coefficients
-8A = 1
A = -1/8
B = 0
yp = -1/8x+0
yp = -x/8 (particular integral)
y = yc+yp
y = A+Be^8x-x/8
