9514 1404 393
Answer:
(c) 1.649
Step-by-step explanation:
For a lot of these summation problems it is worthwhile to learn to use a calculator or spreadsheet to do the arithmetic. Here, the ends of the intervals are 1 unit apart, so we only need to evaluate the function for integer values of x.
Almost any of these numerical integration methods involve some sort of weighted sum. For <em>trapezoidal</em> integration, the weights of all of the middle function values are 1. The weights of the first and last function values are 1/2. The weighted sum is multiplied by the interval width, which is 1 for this problem.
The area by trapezoidal integration is about 1.649 square units.
__
In the attached, we have shown the calculation both by computing the area of each trapezoid (f1 does that), and by creating the weighted sum of function values.
If the factors of the polynomial are (x - 2), (x), and (x + 2). Then the equation of the graph will be (x³ - 4x).
<h3>What is the
equation of the graph?</h3>
The solutions of the graph are 2, 0, and negative 2.
Then the factor can be given as
(x - 2), (x), and (x + 2)
Then the product of the factor will be given below.
(x - 2) × (x) × (x + 2)
x (x² - 4)
x³ - 4x
More about the equation of the graph link is given below.
brainly.com/question/1971145
#SPJ1
(2/3)- students working on math
6-total students
(2/3) of 6 students+= (2/3)x6 = (12/3) = 4
Answer:
I'm not really sure what you're asking because there's no image.
Step-by-step explanation:
please try to reword it and maybe show a picture .