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Elodia [21]
3 years ago
9

Find 4 consecutive even integers such that when three times the smallest of the intagers is added to twice the largest their sum

is 293
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0
If x is the first of the integers then the statement is:

(x) , (x+2) , (x+4) , (x+6)

This means that the smallest is x and the largest is x + 6

so:
3(x) + 2(x+6) = 293
3x + 2x + 12 = 293
5x = 281
x = 56.2
This gives us a none integer (decimal)
What now?

Wait remember how x started as the lowest? what if x was the highest instead?

x, x-2, x-4, x-6
so:

3(x-6) + 2(x) = 293
5x = 315
x = 62.2

This is as close as have gotten to the answer
Cant seem to get an integer.
Maybe error in the question or some bad math on my part.


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Answer:

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

Step-by-step explanation:

We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

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Now, we have to find a value of T, which is found looking at the t table, with 84 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 1.989.

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The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

92% confidence interval:

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The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

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