Introduction to Solving Systems of Equations Theresa and Cary are saving for a printer. Theresa has $10 in the bank and will save $20 each month. Cary has $25 in the bank and will save $15 each month. 1. How much does Theresa have at month #0710 2. How much does Cary have at month #obA 3. Fill in the table for several months. Then graph the data. Use a different color for each girl's table values and graph. Label and scale the axes appropriately Theresa Ca Total Total Month # | Month # | savings in $ (x) savings in $ 0 0 2 2 5 6 6 S 7 4. Write an equation that represents Theresa's savings. yoxtl 5. Write is an equation that represents Cary's savings. tS Which girl is saving at a faster rate? Justify your answer by referring to the 6. table, the graphs, and the equations. 7. At which months does Theresa have more money? 8. At which months does Cary have more money? 9. At which month do they have the same amount of money? What do you notice about the graphs at this month? Introduction to Solving Systems of Equations con... Two friends, Malcolm and Zeke, are going to the park that is near their school. They leave at the same time from different locations. Malcolm is 30 meters from the school on his way to the park, and he is walking at the rate of 1 meter per second. Zeke is at school and will jog to the park at a rate of 4 meters
Step-by-step explanation:
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Answer:
The answer to your question is 0 < x ≤ 3
Step-by-step explanation:
To write this inequality we must consider
- The value of the borders, for this inequality the borders are 0 and 3.
-The kind of border - if it is an open point, we will use the symbol <
- if it is a close c point, we will use the symbol ≤
-The inequality for this problem will be
0 < x ≤ 3
One way in which to do this problem would involve subtracting 5 from 7 (result: 2) and then subtracting 3/5 from 8/9.
To subtract 3/5 from 8/9, you'd need to find the lowest common denominator (LCD) of 3/5 and 8/9, convert both fractions to have this LCD, and then subtract.
The LCD is (5)(9)=45. Then 8/9 and 3/5 become 40/45 and 27/45.
Subtracting 27/45 from 40/45 results in the fraction 13/45.
Then the full solution is 2 13/45.
You could also do this problem by converting 7 8/9 and 5 3/5 into improper fractions:
71/9 - 28/5. Again, the LCD is 45. Can you rewrite both fractions with 45 as the common denominator and then perform the subtraction?
