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3 years ago

HELP ASAP PLEASE I NEED HELP

Mathematics

1 answer:

mariarad [96]3 years ago

5 0

2a) 0.50,0.30
2b) monday and friday
2c) 80degrees

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B) Write 36 as a product of its prime factors.

sukhopar [10]

Answer:2*2*3*3

Step-by-step explanation:

6 0

3 years ago

What is the slope of the line through ( − 5 , − 10 ) (−5,−10)left parenthesis, minus, 5, comma, minus, 10, right parenthesis and

nikdorinn [45]

Answer:

3.75

Step-by-step explanation:

We have to find the slope of a straight line through points (-5,-10) and (-1,5).

Now. we know the slope of a straight line through the points ( $x_{1},y_{1}$ ) and ( $x_{2},y_{2}$ ) is given by $[\frac{y_{2} - y_{1} }{x_{2} - x_{1}} ]$ .

So, in our case ( $x_{1},y_{1}$ ) ≡ (-5,-10) and ( $x_{2},y_{2}$ ) ≡ (-1,5).

Therefore, the slope of the line is $\frac{5 - (- 10)}{- 1 - (- 5)} = \frac{15}{4} = 3.75$ (Answer)

7 0

3 years ago

For what value of k will the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent?

konstantin123 [22]

Answer:

After solve the equations we get value of k=3

Step-by-step explanation:

We need to find value of k for which the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent.

If the lines are concurrent, they pass through same point.

Let:

$x+2y=0--eq(1)\\ 3x-4y-10=0--eq(2)\\ 5x+ky-7=0--eq(3)$

First solving equation 1 and 2 to find values of x and y

From eq(1) we find value of x and put it in eq(2)

$From \ eq(1) x+2y=0\\x=-2y\\Put x=-2y \ in \ eq(2)\\3x-4y-10=0\\3(-2y)-4y-10=0 \\-6y-4y=10\\-10y=10\\y=\frac{10}{-10}\\y=-1$

After solving we get value of y=-1

Now putting in eq(1) to get value of x

$x+2y=0\\x+2(-1)=0\\x-2=0\\x=2$

So, Value of x= 2

Now put value of x=2 and y=-1 into eq(3) to find value of k

$5x+ky-7=0\\5(2)+k(-1)-7=0\\10-k-7=0\\-k+3=0\\-k=-3\\k=3$

So, After solve the equations we get value of k=3

4 0

3 years ago

Factor 1/8 out of 1/8x - 49/8

lord [1]

3 0

3 years ago

Solve pls brainliest

Alexandra [31]

Answer:

v=25.6

Step-by-step explanation:

12.8 x 2 = 25.6 therefore you can check by dividing by 2

7 0

3 years ago

Read 2 more answers