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Anastaziya [24]
3 years ago
9

1. What is the circumference of the given circle in terms of pi? radius= 14 in.

Mathematics
1 answer:
rusak2 [61]3 years ago
5 0

Answer:

1. B     2. B

Step-by-step explanation:

1. The formula for circumference is C= pi times diameter

Radius is half of diameter, so you'd multiply 14 times 2 which gives you 28. Since it's asking for it in pi, it'll be 28 pi.

2. I think instead of circumference, it's asking for area because if it was asking for circumference the answer would have been 6.6 pi, but that answer isn't there. So if it's asking for area, the formula is A= pi(r²) They gave the diameter instead. Remember, the radius is half of the diameter, so in order to get the radius, you'd divide 6.6 by 2 and get 3.3. Then, multiply 3.3 with the number itself, and you'll get 10.89.

Hope this helps!

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Smaller values of the standard deviation result in a normal curve that is
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What type of number is 2 2/3 ? whole number, integer, rational, irrational ?
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The median of Rae's data is 2.22 minutes, and the median of Doris' data is 2.14 minutes. The interquartile range for Rae is , an
JulsSmile [24]

Complete question :

Rae and Doris are training to swim a 200-meter freestyle race. The table lists their practice times during training camp.

Rae’s Times(minutes)-2.12, 2.01, 2.46, 2, 2.22, 2.31, 2.23

doris times(minutes)-2.32, 2.19, 2.26, 2.03, 2.11, 2.14, 2.07

The median of Raes data is(drop down box answers, 2,2.03,2.14,2.22)minutes,and the median of doris data is(drop down box answers, 2,2.03,2.14,2.22)minutes. The interquartile range for rae is(drop down box answers, 0.01,0.13,0.26,0.30), and the interquartile range for doris is(drop down box answers, 0.02,0.06,0.18,0.19). The two data sets overlap(drop down box answers,very little, a lot

Answer:

Rae's median = 2.22

Rae's IQR = 0.30

DORIS median = 2.14

Doris IQR = 0.19

Step-by-step explanation:

Given :

Rae's time :

Ordered data : 2, 2.01, 2.12, 2.22, 2.23, 2.31, 2.46

Median = 1/2(n+1)th term ; n = 7

Median = 1/2(8) = 4th term

Median = 2.22

Q1 = 1/4(8)th term

Q1 = 2nd term = 2.01

Q3 = 3/4(n + 1)th term

Q3 = 3/4(8)th term

Q3 = 6th term = 2.31

Interquartile range = Q3 - Q1 = 2.31 - 2.01 = 0.30

DORIS Data:

Ordered data: 2.03, 2.07, 2.11, 2.14, 2.19, 2.26, 2.32

Median = 1/2(n+1)th term ; n = 7

Median = 1/2(8) = 4th term

Median = 2.14

Q1 = 1/4(8)th term

Q1 = 2nd term = 2.07

Q3 = 3/4(n + 1)th term

Q3 = 3/4(8)th term

Q3 = 6th term = 2.26

Interquartile range = Q3 - Q1 = 2.26 - 2.07 = 0.19

6 0
3 years ago
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