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krek1111 [17]
3 years ago
13

9(x/3+1)>6 can you help me with this.

Mathematics
2 answers:
dybincka [34]3 years ago
7 0

Answer:

the answer is 3 raised ro the third power

algol [13]3 years ago
6 0

Answer:

x > - 1

Step-by-step explanation:

You might be interested in
The time T required to repair a machine is an exponentially distributed random variable with mean 10 hours.
Firdavs [7]

It can be expected about 36.79% of chance that repair time exceeds

The probability that a repair time exceeds  15 hours is 0.3679

What is the exponential distribution?

It explains about the time between events or the distance between two random events is termed the exponential distribution. Here, the occurrence of the events is continuous and also independent. Moreover, the average rate is constant.

The cumulative distribution function of T is obtained below:

From the information given, let the random variable T be the required time to repair a machine follows exponential distribution with parameter λ
with mean. 1/2 hours

That is,  E(x) =  1/2 hours.
The parameter of the random variable T is,
E(x) =  1/λ
λ = 1/E(x)
= 1/(1/2)
= 2

The probability density function of T is,
f(t) = \left \{ {{2e^{-2t} \ \ \ t > 0}  \  \atop {0} \ \ \ elsewhere} \ \right.
The cumulative density function of T is,
FT(t) = P(T <= t)

= 1 - e^{- \lambda t}

= 1 - e^{- 2t}
The CDF of T is,
P(T <= t)  = 1 - e^{- 2t}    0 <= T <= ∞
        = 0          otherwise
to obtain the probability that a repair time exceeds

1/2 hours.
(a) The probability that a repair time exceeds 1/2 hours.
From the given information, the CDF of T is,
P(T <= t)  = 1 - e^{- 2t}    0 <= T <= ∞
        = 0          otherwise

The required probability is,
P(T <= 1/2)  = 1 - P(T <= 1/2)
        = 1 - [  = 1 - e^{- 2(1/2)} ]
       = e^{-1}
= 0.3679

om total probability. It can be expected about 36.79% of chance that repair time exceeds

P(X => x)  = 1 - P(X < x)
to obtain the probability that a repair takes at least 12.5 hours given that its duration exceeds 12 hours.

(b), The probability that a repair takes at least 12.5 hours given that its duration exceeds 12 hours is obtained below:
From the given information, the CDF of T is,
P(T <= t)  = 1 - e^{- 2t}    0 <= T <= ∞
        = 0          otherwise
The required probability is,
P = P(T => 12.5∩T>12) / P(T>12)
= e^{- 25 + 24}

= e^{- 1}
= 0.3679
The probability that a repair takes at least 12.5 hours given that its duration exceeds 12 hours is obtained by dividing the
P = P(T => 12.5∩T>12) / P(T>12)
with
P(T>12).

It can be expected about 36.79% of chance that a repair takes at least 12.5 hours given that its duration exceeds 12 hours.

Hence, It can be expected about 36.79% of chance that repair time exceeds,

The probability that a repair time exceeds  15 hours is 0.3679

To learn more about the product of the fraction visit,
brainly.com/question/22692312
#SPJ4

7 0
1 year ago
|2x+1|&gt;5 what is the answer​<br>solve for real numbers x.
umka2103 [35]

Answer:

see explanation

Step-by-step explanation:

Inequalities of the type | x | > a always have solutions of the form

x < - a or x > a, thus

2x + 1 < - 5 OR 2x + 1 > 5 ( subtract 1 from both sides of both inequalities

2x < - 6 OR 2x > 4 ( divide both sides of both inequalities by 2 )

x < - 3 OR x > 2

4 0
3 years ago
Kira made 4 identical necklaces, each having beads and a pendant. The total cost of the beads and pendants for all 4 necklaces w
snow_lady [41]

Answer: 2.10

Step-by-step explanation: 2.10 * 4 + 6

7 0
3 years ago
Please help will give brainliest
notka56 [123]

Answer:

b

the points make a sad face on the graph  and if you do the vertical line test you can see that its a function

3 0
3 years ago
What is the 3rd square root of 1000
zloy xaker [14]

Answer:

10

Step-by-step explanation:

The third square root is the cube root. This means we are looking for the number that multiplies by itself 3 times to get to 1000, which is 10. (10x10x10=1000)

Hope this helped!

7 0
3 years ago
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