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Murrr4er [49]
2 years ago
9

Whoever gets this in 5 mins will be brainlest

Mathematics
2 answers:
ivanzaharov [21]2 years ago
8 0

Answer:

easy its c

Step-by-step explanation:

so you do you start with the left 2 to the third power is 8

then the right side now is -3 to the second power is -9

in total 8- (9-)

so your answer is -1

hope this helps

Igoryamba2 years ago
7 0

Answer

-1

Step-by-step explanation:

First, you need to plug in your terms for a and b. Now, it should be 2^3 - (-3)^2. Then, do PEMDAS. Solve for the exponent first before subtracting. 2^3 is 8, and (-3)^2 is 9.

After this, you subtract.  8 - 9 is -1, so that is your answer.

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Find an equation of the circle that satisfies the given conditions. Endpoints of a diameter are P(−2, 1) and Q(8, 9)
IrinaK [193]

Answer:

Equation of the circle   (x-3)²+(y-5)²=(6.4)²

                             x² -6x +9 +y² -10y +25 = 40.96

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given endpoints of diameter P(−2, 1) and Q(8, 9)

Centre of circle = midpoint of diameter

                   Centre = (\frac{-2+8}{2} ,\frac{1+9}{2} )

               Centre (h, k) = (3 , 5)

<u><em>Step(ii):-</em></u>

The distance of two end points

PQ = \sqrt{(x_{2}-x_{1} )^{2} +(y_{2} -y_{1} )^{2}  }

PQ= \sqrt{(8+2 )^{2} +(8 )^{2}  }

PQ = √164 = 12.8

Diameter    d = 2r

                 radius r = d/2

                Radius r = 6.4

<u><em>Final answer:-</em></u>

Equation of the circle  

                    (x-h)²+(y-k)² = r²

                   (x-3)²+(y-5)²=(6.4)²

x² -6x +9 +y² -10y +25 = 40.96

x² -6x  +y² -10y  = 40.96-34

x² -6x  +y² -10y -7= 0

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Step-by-step explanation:

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