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KatRina [158]
4 years ago
8

sharon has some almonds. after buying another 350 grams of almonds,she now has 1,230 grams of almonds. How many almond did Sharo

n have at first ?fn
Mathematics
1 answer:
Lilit [14]4 years ago
4 0
880 grams of almonds
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Find the perimeter of a rectangle of which length is 5 more than the width
Leokris [45]

Answer:

<em>the</em><em> </em><em>perim</em><em>eter</em><em>=</em><em> </em><em>1</em><em>0</em><em>+</em><em>4</em><em>W</em><em>.</em>

<em>where</em><em> </em><em>W</em><em>=</em><em> </em><em>the</em><em> </em><em>wid</em><em>th</em><em>.</em>

Step-by-step explanation:

mathematically, perimeter (p)= 2L +2W

where L= length.and W=width

<em>from</em><em> </em><em>the</em><em> </em><em>exp</em><em>ression</em><em> </em><em>;</em><em>length is 5 more than the width</em>

<em>it</em><em> </em><em>is</em><em> </em><em>wri</em><em>tten</em><em> </em><em>as</em><em> </em>L = 5+W

<em>sub</em><em>stitute</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>formu</em><em>la</em><em> </em>

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By the knowledge and application of <em>algebraic</em> definitions and theorems, we find that the expression - 10 · x + 1 + 7 · x = 37 has a solution of x = 12. (Correct choice: C)

<h3>How to solve an algebraic equation</h3>

In this question we have an equation that can be solved by <em>algebraic</em> definitions and theorems, whose objective consists in clearing the variable x. Now we proceed to solve the equation for x:

  1. - 10 · x + 1 + 7 · x = 37     Given
  2. (- 10 · x + 7 · x) + 1 = 37   Associative property
  3. -3 · x + 1 = 37     Distributive property/Definition of subtraction
  4. - 3 · x = 36     Compatibility with addition/Definition of subtraction
  5. x = 12     Compatibility with multiplication/a/(-b) = -a/b/Definition of division/Result

By the knowledge and application of <em>algebraic</em> definitions and theorems, we find that the expression - 10 · x + 1 + 7 · x = 37 has a solution of x = 12. (Correct choice: C)

To learn more on linear equations: brainly.com/question/2263981

#SPJ1

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