Question

2^2/5+ 3^1/10 HELP ASAP

Answer 1

Answer:

$\sqrt[5]{4}$  + $\sqrt[10]{3}$

Step-by-step explanation:

We sure can write 2^2/5+ 3^1/10 as $2^{\frac{2}{5} } + 3^{\frac{1}{10} }$

// use the $a^{\frac{m}{n} } =\sqrt[n]{a^{m} }$ to transform the expression

Convert $2^{\frac{2}{5} }$ to $\sqrt[5]{2^{2} }$ = $\sqrt[5]{4}$                        (here a = 2, n = 5, m = 2)

Then convert  $3^{\frac{1}{10} }$ to $\sqrt[10]{3^{1} }$ = $\sqrt[10]{3}$             (here a = 3, n = 10, m = 1)

Now we get  $2^{\frac{2}{5} } + 3^{\frac{1}{10} }$ = $\sqrt[5]{4}$  + $\sqrt[10]{3}$ . This is the simplified form, which is the answer.