What is the area of an isosceles triangle with side lengths of 22 and 66
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to increase each dimension by equal lengths so that its area triples is 12 feet.
The given dimensions are 18 feet by 15 feet.
We need to find how much should each dimension increase.
Shaquana wants to increase each dimension by equal lengths so that its area triples.
Let the increased length be x.
So, length =18+x feet and width=15+x feet.
As we know, the area of a deck=Length×Width
The original area of a deck=18×15=270 square feet.
Now, the new area of a deck=(18+x )×(15+x)=3×270
⇒270+15x+18x+x²=810 square feet
⇒x²+33x-540=0
Here, a=1, b=33 and c=-540 in .
⇒
⇒
⇒x=-45 or x=12
Length can not be a negative integer.
Therefore, to increase each dimension by equal lengths so that its area triples is 12 feet.
To learn more about the area of a rectangle visit:
brainly.com/question/20693059.
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