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MatroZZZ [7]
3 years ago
11

The __________ are tubular, fluid-filled structures that provide information about head rotations and movements.

Physics
2 answers:
shusha [124]3 years ago
4 0

Answer: C

Explanation:

The semi-circular canals are tubular, fluid-filled structures that provide information about head rotations and movements.

The semi-circular canals match the description. Therefore, it is the answer.

Hope this helps!

NNADVOKAT [17]3 years ago
4 0

Answer:

The <u>semicircular canals </u> are tubular, fluid-filled structures that provide information about head rotations and movements.

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Plz help me im really confused. The questions are in the second pic and the vehicles are in the first the fetures are in the las
kirill115 [55]

Answer:

1.ima say car 2 is safer than car 1.

2.airbags: airbags make it safer because if you get in a reck they will protect you againsed more harm then if you didnt have airbags.

breaking distance: it takes less distance to stop so if there was a reck up the streat you could stop and turn around so you wouldnt get into that wreck.

accrleration: it can make you go faster so incase someoe behind you is speading you could speadup and turn into a parking lot and you wouldent get hurt.

3. car 2 is safer because it has breaking distance and it can stop you way before you get into a wreck than car 1 that doesnt have that ability

Explanation: ima award myself brainliest. Dont ask why i just answerd my own question on here. Yay

5 0
3 years ago
What factors are required for refraction to occur PLEASE HELP!
Cloud [144]
1. Light Travelling from denser medium to less dense medium

2. Light Travelling from less dense medium to denser medium

5 0
3 years ago
A charging RC circuit controls the intermittent windshield wipers in a car. The emf is 12.0 V. The wipers are triggered when the
lilavasa [31]

Answer:

R=803k\Omega

Explanation:

We have the following information,

V_0 = 12V\\V=10V\\c= 1.25*10^{-6}F\\t=1.8s

We apply the equation for capacitor charging the voltage across it,

V=V_0 (1-e^{-t/x})\\e^{-t/x}=1-(\frac{V}{V_0})\\-\frac{t}{Rc}=ln(\frac{V}{V_0})\\R=-\frac{t}{ln(\frac{V}{V_0})*c}

Replacing values,

R=-\frac{1.8}{ln(10/12)*1.25*10^{-6}}

R=803k\Omega

3 0
3 years ago
A 817 kg car has four 8.91 kg wheels. When the car is moving, what fraction of the total kinetic energy of the car is due to rot
KATRIN_1 [288]

Answer:

0.0107

Explanation:

We know that

The rotational kinetic energy due to four wheel is

1/2ဃ²I x 4

So

1/4mR²(v/R)² = mv²

But kinetic energy along straight path of the car is 1/2mv²

=> 1/2( 817)v ²

Kc= 408.5v²

So The fraction of total kinetic energy that is due to rotation of the wheel about their axis

Is Kw/Kw+Kc

and Kw = 1/2* 8.91v²= 4.45v²

So 4.45v²/ 4.45v²+ 408.5v²

= 0.0107 as fraction of total kinetic energy

8 0
3 years ago
What is the displacement from 4 to 10 seconds? How do you know?
Strike441 [17]
For velocity vs time graphs, you can calculate displacement by finding the area between the line and the x-axis (time line). You should be able to recognize that space between the lines as a triangle, trapezoid, square, or rectangle and use the respective area formulas for these shapes.

See attached photo for worked out solution.

4 0
3 years ago
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