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3 years ago

Answer all of these questions and you will get the brainlist

Physics

2 answers:

adelina 88 [10]3 years ago

6 0

Answer:

1. kinetic energy = ½mv²

m= 2.1 kg

v = 30m/s

Ek = ½ ×2.1×30×30

= 945J

2. potential energy = mgh

m = 190kg

g = 9.8

h = 45m

Ep = 190×9.8 × 45

= 83790J

3.potential energy = mgh

m= 75kg

g= 9.8

h = 300m

Ep = 75×9.8×300

= 220,500J

Gnoma [55]3 years ago

5 0

Answer:

2 ans : the bell has 8550 J energy

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2 years ago

Compare the gravitational acceleration on the following objects compared to the Sun using:

arsen [322]

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The gravitational acceleration of Neutron star compared to Sun is 6.79 x 10⁻²⁴.

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<h3>Mass of the planets</h3>

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Mass of white dwarf = 2.765 x 10³⁰ kg

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Mass of star Betelgeuse = 2.188 x 10³¹ kg

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$\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{2.765 \times 10^{30}}{2\times 10^{30}} \times [\frac{696,340,000}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 13,675.86$

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$\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{5.5 \times 10^{12}}{2\times 10^{30}} \times [\frac{11,000}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 6.79\times 10^{-24}$

<h3>Gravitational acceleration of Star Betelgeuse compared to Sun</h3>

$\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{2.188 \times 10^{31}}{2\times 10^{30}} \times [\frac{617.1 \times 10^9}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 8.5\times 10 ^{10}$

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