2 hours = 60*2 = 120 minutes
120/120 = 1
Margie handed out 1 flyer every minute
Jaxon handed 18/15 = 1.2 flyers per minute
so Jaxon is faster
Parallel lines should have the same slope. Therefore, you know which point it passes through and the slope. Plug in the points and slop into slope-intercept form to find b. Please refer to the picture.
Answer:
Part 1) 
Part 2) 
Part 3) 
Step-by-step explanation:
<u><em>The complete question is</em></u>
Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B
The picture of the question in the attached figure
Part 1) Write the ratio equivalent to: Sin B
we know that
In the right triangle ABC
----> by SOH (opposite side divided by the hypotenuse)
substitute the values

Part 2) Write the ratio equivalent to: Csc A
we know that
In the right triangle ABC

-----> by SOH (opposite side divided by the hypotenuse)
substitute the values

therefore

Part 3) Write the ratio equivalent to: Cot A
we know that
In the right triangle ABC

-----> by TOA (opposite side divided by the adjacent side)
substitute the values

therefore

Add powers of 3.
1 + 3 = 4
4 + 9 = 13 = 4 + 3^2
13 + 27 = 40 = 13 + 3^3
40 + 81 = 121 = 40 + 3^4
Now you need to add 3^5 to 121.
121 + 3^5 = 121 + 243 = 364