(a+b)^2= hihihihihhiih
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Answer:
Step-by-step explanation:
Given that Elijah threw a ball from a height of 4 feet. The ball reached maximum height of 16 feet after 2seconds
Let vertical component of his speed be v
When it reaches maximum height its velocity becomes 0
Hence
height reached by the ball =
When h=12(16-4) we get g=gravity =32
Hence 12 =2v-16(4)
v=38
Hence
where h is calculated from the height of hand i.e. 4 feet
When it touches the ground h =-4
When it starts falling then distance travelled = 16 feet
Initial velocity =0 Accn due to gracity =32 feet
Using these we can write
So after 3 minutes from start the ball would reach the ground