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zhuklara [117]
3 years ago
15

Write a recursive formula and an explicit formula for the following arithmetic sequence.

Mathematics
1 answer:
xenn [34]3 years ago
4 0

Answer:

Please check the explanation.

Step-by-step explanation:

Given the sequence

11, 13, 15, 17, 19, ...

Determining the Recursive formula:

We know that a recursive formula is termed as a formula that specifies each term of the given sequence using the preceding terms.

From the given sequence it is clear that every term can be obtained by adding two to the previous term.

i.e. 13 = 11+2, 15 = 13+2, 17 = 15+2, 19 = 17+2

so

aₙ₊₁ = aₙ+2, for n ≥1

Therefore, a recursive formula is:

  • aₙ₊₁ = aₙ+2, for n ≥1

Determining the Explicit formula:

Given the sequence

11, 13, 15, 17, 19, ...

An arithmetic sequence has a constant difference 'd' and is defined by  

a_n=a_1+\left(n-1\right)d

computing the differences of all the adjacent terms

3-11=2,\:\quad \:15-13=2,\:\quad \:17-15=2,\:\quad \:19-17=2

The difference between all the adjacent terms is the same and equal to

d=2

also

a_1=11

so substituting d=2, a_1=11 in the nth terms

a_n=a_1+\left(n-1\right)d

a_n=2\left(n-1\right)+11

a_n=2n+9

Therefore, the Explicit formula is:

a_n=2n+9

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3 years ago
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den301095 [7]

Answer:

-1

Step-by-step explanation:

We need to simplify the given expression . The given expression is ,

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Using this property , we have ,

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\rm\implies\{( 2 \sqrt6 +5) ( 2\sqrt6 - 5)\}^{2n-1}

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\rm\implies\boxed{\quad \red{ -1 }\quad }

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Given,

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7 0
1 year ago
The common ratio in a geometric series is 0.5 and the first term is 256. Find the sum of the first 6 terms in the series
Svetach [21]

Answer:

The sum of the first 6 terms of the series is 504.

Step-by-step explanation:

Given that,

Common ratio in a geometric series is, r = 0.5

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3 years ago
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