Answer:
y = -4x +2
Step-by-step explanation:
As x-values increase by 1, y-values decrease by 4. The slope of the line is ...
... m = (change in y)/(change in x) = -4/1 = -4
We can use the first (x, y) pair as a point to use in the point-slope form of the equation of a line. That form can be written, for slope m and point (h, k) ...
... y = m(x -h) +k
using m = -4 and (h, k) = (1, -2), we can fill in the numbers to get ...
... y = -4(x -1) -2
... y = -4x +4 -2 . . . . eliminate parentheses
... y = -4x +2 . . . . . . slope-intercept form
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<em>Alternate approach</em>
After you recognize that a change in x of 1 gives a change in y of -4, you can work backward one step to find the table value for y corresponding to x=0. That will be -2+4 = +2. Now, you know both the slope (-4) and the y-intercept (+2), so you can write the equation directly from this knowledge:
... y = -4x +2
Answer:
Bonds: $42,000
Certificates of deposit: $41,000
Step-by-step explanation:
Total invested = Amount in bonds + Amount in CDs
Amount in bonds = Amount in CDs + 1000
Let the amount in bonds = B and the amount in CDs = C
1. 83,000 = B + C
2. B = C+1000
Since the above expression (#2) defines B, you can substitute it for the B in the first equation (#1).
83,000 = C + 1000 + C
Now, you can solve for C.
83,000 = 2C + 1000
82,000 = 2C
41,000 = C
You know that the amount invested in bonds is $1000 greater than the amount invested in CDs, so add $1000 to C and you find B, $42,000.
<span>15-h)*h=40
15h-h^2=40
h^2-15h+40=0
solve for h by quadratic formula:
a=1, b=-15, c=20
ans:
h=3.47 or 11.53 cm (height)
b=15-h=11.53 or 3.47 cm (base)</span>
Answer:
Ok, we know that we can write a horizontal translation as:
y' = f(x - A)
where if A is positive, this moves the graph of f(x) A units to the right.
Why is this?
Ok, let's compare:
y = f(x)
and
y' = f(x - A)
in y, when x = 0 we have f(0).
While to have this same point in y', we need to evaluate in x = A.
f(A - A) = f(0).
Then the value f(0) is now at x = A, this means that the point moved A units to the right.
And you can do this for all the values, so you will find that the entire graph of f(x) has ben moved A units to the right.
Represent the number of days by x. With this representation, the variable cost of the rental is 31.67x. The total cost is the sum of the fixed and variable costs. This value should not be more than $500. The equation below shows the relationship.
130 + 31.67x ≤ 500
Solving for x gives x ≤ 11.68
Thus, the maximum number of days to rent the car is only 11 days.