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Ymorist [56]
3 years ago
5

Factor completely n^4-1

Mathematics
2 answers:
taurus [48]3 years ago
4 0
N^4 - 1 = (n^2 - 1)(n^2 + 1)

            =     (n + 1)(n - 1)(n^2 + 1)
Effectus [21]3 years ago
4 0

Answer:(n + 1)(n - 1)(n^2 + 1)

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Step2247 [10]

Answer:

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Step-by-step explanation:

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3 years ago
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What’s the solution to this equation 2+x=7/8x-15
Nostrana [21]

Answer:x=−136

Step-by-step explanation: Step 1: Simplify both sides of the equation.

2+x=

7

8

x−15

2+x=

7

8

x+−15

x+2=

7

8

x−15

Step 2: Subtract 7/8x from both sides.

x+2−

7

8

x=

7

8

x−15−

7

8

x

1

8

x+2=−15

Step 3: Subtract 2 from both sides.

1

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x+2−2=−15−2

1

8

x=−17

Step 4: Multiply both sides by 8.

8*(

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x)=(8)*(−17)

6 0
3 years ago
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Solve this equation 90x-60y is equal to 68 and 90x-70y is equal to 91​
Tanzania [10]

Answer:

Step-by-step explanation:

90x - 60y = 68.....multiply by -1

90x - 70y = 91

---------------------------

-90x + 60y = -68 (result of multiplying by -1)

90x - 70y = 91

---------------------------add

-10y = 23

y = -23/10 <===

90x - 60y = 68

90x - 60(-23/10) = 68

90x + 138 = 68

90x = 68 - 138

90x = - 70

x = -70/90

x = -7/9 <=====

3 0
3 years ago
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6 0
3 years ago
When 5 times a number is added to 45 the answer is the sm of 85 and 140 what is the number
zimovet [89]

Hello.

First, let the number be r.

5 times r is written like this:

\rm{5r}

Now, add 45:

\mathrm{5r+45}

Now, the sum of 5r+45 is equal to the sum of 85 and 140:

\mathrm{5r+45=85+140}

In order to solve this equation, we need to add 85 and 140:

\mathrm{5r+45=225}

Now, subtract 45 from both sides:

\mathrm{5r+45-45=225-45}

\mathrm{5r=225-45}

\mathrm{5r=180}

The last step is to divide both sides by 5:

\mathrm{r=36}

Therefore, the answer is

\rm{r=36}

I hope it helps.

Have a nice day.

\boxed{imperturbability}

8 0
2 years ago
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