The options in the question are:
a) +0.46 V
b) +0.617 V
c) +1.39 V
d) -0.46 V
e) +1.21 V
Answer:
b) +0.617 V
Explanation:
The equation shows that the anode is Sn2+/Sn4+ while the cathode is Fe3+/Fe2+.
The E° cell is obtained from E°cathode - E°Anode
E°cathode= 0.154V
E°Anode= 0.771V
E° cell= E°cathode - E°Anode= 0.771-0.154=0.617
Answer:
9.90
Explanation:
-log(H3O+)=pH
- Hope that helps! Please let me know if you need further explanation.
Answer:
52.54 %
Explanation:
Half life = 29 years
Where, k is rate constant
So,
The rate constant, k = 0.023902 hour⁻¹
From 1964 to 1991:
Time = 27 years
Using integrated rate law for first order kinetics as:
![[A_t]=[A_0]e^{-kt}](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5BA_0%5De%5E%7B-kt%7D)
Where,
![[A_t]](https://tex.z-dn.net/?f=%5BA_t%5D)
is the concentration at time t
![[A_0]](https://tex.z-dn.net/?f=%5BA_0%5D)
is the initial concentration
So,
![\frac {[A_t]}{[A_0]}=e^{-0.023902\times 27}](https://tex.z-dn.net/?f=%5Cfrac%20%7B%5BA_t%5D%7D%7B%5BA_0%5D%7D%3De%5E%7B-0.023902%5Ctimes%2027%7D)
![\frac {[A_t]}{[A_0]}=0.5245](https://tex.z-dn.net/?f=%5Cfrac%20%7B%5BA_t%5D%7D%7B%5BA_0%5D%7D%3D0.5245)
<u>The strontium-90 remains in the bone = 52.54 %</u>
