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zalisa [80]
3 years ago
13

Triple covalent bond can be formed between:

Chemistry
1 answer:
marta [7]3 years ago
3 0
A triple covalent bond can be formed between d) C & O
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Balance the chemical equation. Based on the equation, how many grams of bromine are produced by the complete reaction of 11 gram
scoundrel [369]

Answer:

Explanation:

The balanced chemical equation is Cl2 + 2KBr → 2KCl + Br2. The amount of bromine is calculated as follows:

11.0 g KBr (1mol KBr/119.002g KBr * 1mol Br2/2mol KBr * 159.808g Br2/1mol Br2= 7.39 g Br2.)

5 0
3 years ago
What type of wave produces sound?
kari74 [83]

El sonido es una onda que se crea por vibración y se propaga a través de un medio de un punto a otro. De modo que es basicamente una onda mecánica longitudinal.

Es una onda mecánica pues necesita un medio para propagarse,

5 0
3 years ago
I NEED HELP FAST!!!!! Can you tell me about examples of elements compounds and mixtures??? I have a DBA in a few minutes and I d
Jet001 [13]
Okay Elements can combine to created element compounds a few examples can be lets say Gold(Au) Is an example of an Iconic Compound (usually a common compound). An Element Mixture is literal a mixture Ex. Brass. Brass is usually 10% copper and 45% zinc. So in order to get Brass you must physically m<span />ix copper with zinc and the other metal (sorry i don't remember the name) Also mixtures tend to not be chemically constant, this is because it was physically mixed rather than all of the atoms be the same if they were chemically combined.
3 0
4 years ago
What volume (in mL ) of 0.200   M NaOH do we need to titrate 40.00 mL of 0.140   M HBr to the equivalence point?
Ugo [173]
NaOH + HBr =⇒ NaBr + H2O

35.0 ml HBr x 1 liter/1000 mL x 0.140 moles HBr/ liter = 0.0049 moles HBr

0.0049 moles HBr x 1mole NaOH/1mole HBr = 0.0049 moles HBr

0.0049 moles HBr x 1 liter NaOH/0.200 moles NaOH x 1000 mL/1liter= 24.5 mL NaOH
7 0
3 years ago
Read 2 more answers
In one of his experiments, Lavoisier placed 10.0 grams of mercury (II) oxide into a sealed container and heated it. The mercury
inysia [295]

Oxygen gas produced : 0.7 g

<h3>Further explanation</h3>

Given

10.0 grams HgO

9.3 grams Hg

Required

Oxygen gas produced

Solution

Reaction⇒Decomposition

2HgO(s)⇒2Hg(l)+O₂(g)

Conservation of mass applies to a closed system, where the masses before and after the reaction are the same

mass of reactants = mass of products

mass  HgO = mass Hg + mass O₂

10 g = 9.3 g + mass O₂

mass O₂ = 0.7 g

4 0
3 years ago
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