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stepan [7]
3 years ago
7

A mother spins her son in a circle of radius R at angular

Physics
1 answer:
cluponka [151]3 years ago
4 0

A body has centripetal acceleration with magnitude <em>a</em> such that

<em>a</em> = <em>v</em> ² / <em>R</em>

where <em>v</em> is the body's tangential speed and <em>R</em> is the radius of the circular path the body takes.

Convert the child's angular speed <em>ω</em> into linear/tangential speed. Assume angular speed is measured in rad/s and tangential speed in m/s. For every 2<em>π</em> rad that he revolves around his mother, the child travels a distance of 2<em>πR</em> m, so that

<em>ω</em> = (<em>ω</em> rad/s) • (2<em>πR</em>/(2<em>π</em>) m/rad) = <em>Rω</em> = <em>v</em>

Then the child's acceleration is

<em>a</em> = (<em>Rω</em>)² / <em>R</em> = <em>Rω</em> ²

When the mother pulls her arms in, the distance <em>R</em> gets halved and changes to <em>R</em>/2, so that the child's new acceleration is

<em>a</em> = (<em>R</em>/2 • <em>ω</em>)² / (<em>R</em>/2) = (1/4 • (<em>Rω</em>)²) / (1/2 • <em>R</em>) = 1/2 <em>Rω</em> ²

so the child's centripetal acceleration decreases by a factor of 2.

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